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enot [183]
3 years ago
13

The vertex of this parabola is at (-3, -1). When the y-value is 0, the x-value is 4. What is the coefficient of the squared expr

ession in the parabola's equation?
Mathematics
2 answers:
expeople1 [14]3 years ago
8 0

Answer:   \bold{\dfrac{1}{49}}

<u>Step-by-step explanation:</u>

The vertex form of a quadratic equation is: y = a(x - h)² + k   where

  • "a" is the coefficient
  • (h, k) is the vertex

Since the given information is (h, k) = (-3, -1)  and (x, y) = (4, 0), we can input those values into the vertex form and solve for "a":

0 = a[4 - (-3)]² + (-1)

0 = a(4 + 3)² - 1

0 = a(49) - 1

1 = 49a

\dfrac{1}{49}=a

Klio2033 [76]3 years ago
6 0

Answer:

S(-3, -1)

P(4, 0)

a = (Py - Sy) / (Px - Sx)^2

a = (0 - (-1)) / (4 - (-3))^2

a = 1 / 7^2

<u>a = 1 / 49</u>

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HELP
larisa86 [58]
It looks like the parabola are going down, so  the coefficient should be negative,
B or C,
then we see that the parabola has x -intercepts (1,0) and (5,0)
these roots should be written as multiples 
x=1, so x-1=0
and 
x=5, so x-5=0,
so (x-1)(x-5) and negative first coefficient -2 at the same time. 
We can see only in the 
B. <span>f(x) = –2(x – 5)(x – 1)</span>
7 0
3 years ago
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