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4 years ago

NEED HELP ASAP! What is the value of x? x =

Mathematics

1 answer:

rjkz [21]4 years ago

7 0

The Intersecting Secant Theorem says

EC × ED = EB × EA

(x+4)(x+4+1) = (x+1)(x+1+11)

(x+4)(x+5)=(x+1)(x+12)

x^2 + 9x + 20 = x^2 + 13 x + 12

8 = 4x

x = 2

Check:

6(7)=42

3(14)=42, good

Answer: 2

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3 years ago

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3 years ago

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olya-2409 [2.1K]

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3 years ago

Adjoint of [1 0 2 -1] is

aliina [53]

The adjoint of the matrix $\left[\begin{array}{cc}1&0\\2&-1\end{array}\right]$ is $\left[\begin{array}{cc}-1&0\\-2&1\end{array}\right]$

<h3>How to determine the adjoint?</h3>

The matrix is given as:

$\left[\begin{array}{cc}1&0\\2&-1\end{array}\right]$

For a matrix A be represented as:

$A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

The adjoint is:

$Adj = \left[\begin{array}{cc}d&-b\\-c&a\end{array}\right]$

Using the above format, we have:

$Adj = \left[\begin{array}{cc}-1&0\\-2&1\end{array}\right]$

Hence, the adjoint of the matrix $\left[\begin{array}{cc}1&0\\2&-1\end{array}\right]$ is $\left[\begin{array}{cc}-1&0\\-2&1\end{array}\right]$