Joseph buys 10 cookies. He eats 7 of them. He wants to know how many cookies he has left.

Expand (2x+2)^6 How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

8 0

1 year ago

This is my last question by the way

Leni [432]

Part A:

There are 25 blocks for the length, and the length of each is 5.5 inches. 5.5x25=137.5

There are 9 blocks for the height, and each is 2.75 inches. 2.75x9=24.75

Since we're trying to find how much longer the length is to the width, we find the difference. 137.5-24.75=112.75

So part A answer is 112.75 (or 112¾)

Part B:

We know the length is 137.5 and the height is 24.75. To find how many times longer the length is, we need to divide to see how many 24.75 can go into 137.5.

137.5÷24.75=5.55

So the answer to part B is 5.55. Given the context, the answer would probably be 5, because that's how many entire height can fit.

Sorry if it's wrong lol

8 0

3 years ago

I need help pls. Question 11

g100num [7]

Answer:

T = .17m + 50

Step-by-step explanation:

T = Total cost

M = Mile

3 0

3 years ago

Explain why a graph that fails the vertical-line test does not represent a function. Be sure to use the definition of function i

777dan777 [17]

Answer:

The vertical line test can be used to determine whether a graph represents a function. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.

Step-by-step explanation:

The vertical line test can be used to determine whether a graph represents a function. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.

I attached an Image you can visualize it clearly

P.S I ain't that good at drawing though :P

3 0

3 years ago

Can u find a it please

blsea [12.9K]

Answer:

3 + 3 + 1

Step-by-step explanation:

The doubles is 3+3 which is 6 plus 1 is 7

6 0

3 years ago