Answer:
i think b and d
Step-by-step explanation:
15x.25=3.75
15-3.75=11.25.
The answer is $11.25
Given
P(1,-3); P'(-3,1)
Q(3,-2);Q'(-2,3)
R(3,-3);R'(-3,3)
S(2,-4);S'(-4,2)
By observing the relationship between P and P', Q and Q',.... we note that
(x,y)->(y,x) which corresponds to a single reflection about the line y=x.
Alternatively, the same result may be obtained by first reflecting about the x-axis, then a positive (clockwise) rotation of 90 degrees, as follows:
Sx(x,y)->(x,-y) [ reflection about x-axis ]
R90(x,y)->(-y,x) [ positive rotation of 90 degrees ]
combined or composite transformation
R90. Sx (x,y)-> R90(x,-y) -> (y,x)
Similarly similar composite transformation may be obtained by a reflection about the y-axis, followed by a rotation of -90 (or 270) degrees, as follows:
Sy(x,y)->(-x,y)
R270(x,y)->(y,-x)
=>
R270.Sy(x,y)->R270(-x,y)->(y,x)
So in summary, three ways have been presented to make the required transformation, two of which are composite transformations (sequence).
Answer:

Step-by-step explanation:
<u>Given </u><u>:</u><u>-</u><u> </u>
And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,
<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>
<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>
- If we have a logarithmic equation as ,
Then this can be written as ,
In a similar way we can write the given equation as ,
- Now also we know that
Therefore , the equation becomes ,
<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>
I think that -25 should be +25.
so it would be (7x-5)^2