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stellarik [79]
2 years ago
6

HELP PLEASE if I don’t turn this in it’ll make my grade drop to a 60% I will give brainiest to whoever answers this!

Mathematics
1 answer:
GenaCL600 [577]2 years ago
7 0
2) Larger triangle is twice as large as the smaller one so x is 16
3) 16/12.8= 1.25 (This is the scale factor)
for y: 10/1.25=8
for x: 30/1.25=16
4) 8/6.4=1.25 (Scale factor)
for y: 14/1.25=11.2
for x: 15/1.25= 12
5) 22.5/9= 2.5 (scale factor)
for x: 12x2.5=30
for y: 35/2.5= 14
6) No because the scale factor is 2 but 14/8 does not equal to 2
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valina [46]

Answer:

i think b and d

Step-by-step explanation:

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2 years ago
Marshall wants to buy a picture frame. The original price is $15,
lakkis [162]
15x.25=3.75
15-3.75=11.25.

The answer is $11.25
4 0
2 years ago
PLEASE HELP ASAP. RIGHT ANSWER WILL GET BRAINLIEST
dimulka [17.4K]
Given
P(1,-3); P'(-3,1)
Q(3,-2);Q'(-2,3)
R(3,-3);R'(-3,3)
S(2,-4);S'(-4,2)

By observing the relationship between P and P', Q and Q',.... we note that
(x,y)->(y,x)  which corresponds to a single reflection about the line y=x.
Alternatively, the same result may be obtained by first reflecting about the x-axis, then a positive (clockwise) rotation of 90 degrees, as follows:
Sx(x,y)->(x,-y)    [ reflection about x-axis ]
R90(x,y)->(-y,x)    [ positive rotation of 90 degrees ]
combined or composite transformation
R90. Sx (x,y)-> R90(x,-y) -> (y,x)

Similarly similar composite transformation may be obtained by a reflection about the y-axis, followed by a rotation of -90 (or 270) degrees, as follows:
Sy(x,y)->(-x,y)
R270(x,y)->(y,-x)
=>
R270.Sy(x,y)->R270(-x,y)->(y,x)

So in summary, three ways have been presented to make the required transformation, two of which are composite transformations (sequence).
4 0
3 years ago
Read 2 more answers
What are the potential solutions of In(x^2-25)=0?
Maslowich

Answer:

x =\pm \sqrt{26}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>

\implies log_e {(x^2-25)}= 0

<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>

  • If we have a logarithmic equation as ,

\implies log_a b = c

Then this can be written as ,

\implies a^c = b

In a similar way we can write the given equation as ,

\implies e^0 = x^2 - 25

  • Now also we know that a^0 = 1 Therefore , the equation becomes ,

\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}

<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>

6 0
2 years ago
MATH HELP PLEASE I WILL MARK BRAINLIEST !!!! WHY IS THIS NOT FACTORABLE ?
Leya [2.2K]

I think that -25 should be +25.

so it would be (7x-5)^2

8 0
3 years ago
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