Question

The drop that riders experience on Dr. Doom's Free Fall can be modeled by the quadratic function, /?f=h%28t%29%3D-9.8t%5E%7B2%7D%20-5t%2B39" id="TexFormula1" title="h(t)=-9.8t^{2} -5t+39" alt="h(t)=-9.8t^{2} -5t+39" align="absmiddle" class="latex-formula"> where h is height in meters and t is time in seconds. Show your work for each parts.
Part A: What is the starting height of riders?

Part B: According to the function, when will the height of the riders equal 0?

Part C: Will the height ever actually equal 0? Why or why not?

Answer 1

Answer:

  A. 39 m

  B. approximately t = 1.756 seconds

  C. maybe; it depends on the design of the ride (and the accuracy of the model)

Step-by-step explanation:

Part A:

The "starting" value is generally understood to be the value when t=0. Here, we have ...

  h(0) = -9.8·0² -5·0 +39 = 0 +0 +39 = 39

The starting height is 39 meters.

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Part B:

The height of the riders will be 0 for the value of t that makes h(t) = 0. That is the solution to the equation ...

  -9.8t² -5t +39 = 0

Using the quadratic formula, the solution for ax²+bx+c = 0 is ...

  x = (-b±√(b²-4ac))/(2a) . . . . . . . we have a=-9.8, b=-5, c=39

Then the time can be found to be ...

  t = (-(-5)±√((-5)²-4(-9.8)(39)))/(2(-9.8)) = (-5±√1553.8)/19.6

  t ≈ (-5 ± 39.4183)/19.6 ≈ {-2.266, +1.756}

Only the positive solution is of interest, so ...

  t ≈ 1.756 . . . seconds

The height of the riders will equal 0 about 1.756 seconds after the start of the ride.

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Part C:

To the extent that the given function accurately models the height of a rider, there does exist a time at which the rider's height is actually zero. There may be any of a number of reasons why the rider's height may not be zero:

• the model is not completely accurate for values of h(t) near 0. (The ride design may have a minimum positive height, for example.)
• the domain of the function does not include the time when the rider's height is zero