Let's call the 13¢ stamps a and the 18¢ stamps b:
a+b = 42 and therefore a= 42-b (formula 1)
0.13a+0.18b= 6.66 In this formula, substitute the value of a according to formula 1:
0.13(42-b)+0.18b= 6.66 Multiply on the left to get rid of the parenthesis:
5.46-0.13b+0.18b= 6.66 Subtract 5.46 from both sides:
-0.13b+0.18b= 1.20 Add on the left:
0.05b= 1.20 Divide both sides by 0.05
b= 24 You have 24 18¢ stamps and:
42-24= 18 13¢ stamps
Check: (24 x 0.18) + (18 x 0.13)= 6.66 Correct.
Answer:
8x + 4 - z
Step-by-step explanation:
Given the following :
The distance from her house to school is 2x+5 The distance from the school to the park is z If the total distance she was that day is 10x +9 how far is it from the park back to her
Distance from house to school = 2x + 5
Distance from school to park = z
Total distance covered = 10x + 9
Distance from park to house =?
Total distance = (distance from house to school + distance from school to park + distance from park to house)
Let p = distance from park to house
10x + 9 = (2x + 5 + z + p)
10x + 9 - 2x - 5 - z = p
8x + 4 - z
Answer:
Step-by-step explanation:
(2x−12)^2 can be factored into 2^2*(x - 6)^2, which in turn becomes
4(x^2 - 12x + 36). Yes, this is a special product of the form
(a - b)^2 = a^2 - 2ab + b^2.
Answer:
it D
Step-by-step explanation:
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