The sum of five consecutive positive integers is 2020. Find the largest of these numbers.
1 answer:
Answer:
406
Step-by-step explanation:
Five consecutive positive integers = x, (x+1), (x+2), (x+3), (x+4)
x + (x+1) + (x+2) + (x+3) + (x+4) = 2020
5x + 10 = 2020
5x = 2020-10
5x = 2010
x = 2010÷5
x = 402
The largest of the number is = x+4
x+4 = 402 + 4 = 406
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