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Andreyy89
2 years ago
14

What was the significance of the 1876 election brainly.

SAT
1 answer:
Komok [63]2 years ago
7 0

Answer:To date, it remains the election that recorded the smallest electoral vote victory (185–184), and the election that yielded the highest voter turnout of the eligible voting age population in American history, at 81.8%.

Explanation:

You might be interested in
If point E(5, h) is on the line that contains A(0, 1) and B(−2, −1), what is the value of h?
nikdorinn [45]
First calculate the change in y over the change in x:

by - ay -1 - 1 -2
———— = ——— = —— = 1
bx - ax -2 - 0 -2


The slope is 1:

Second set up the equation in y = mx + b form (m is your slope!) ...

y = (1)x + b

... and plug in either point you have used (A or B)

A(0,1)

1 = (1)(0) + b
1 = b

Now you have your equation: y = 1x + 1

Your final step is to plug in point C to solve for your missing variable:

y = (1)(5) + 1
y = 6

the value of H therefore is 6
3 0
3 years ago
The length of the apothem of the hexagon is about inches. the perimeter of the hexagon is inches. the area of the hexagon is abo
Ulleksa [173]

Answer: 13.9 | 96.0 | 667.2 |

Explanation:

8 0
1 year ago
How do you solve this kind of problem?
katen-ka-za [31]
First, we want to solve for b.

In order to solve for b, we plug in x=6 and f(x)=7 into the equation, since we know f(6)=7

7 = (3/2)(6) + b

7 = 9 + b

Subtract both sides by 9

b = -2

Now, let's insert this value into the equation

f(x) = (3/2)x - 2

Now, plug in x = -2 into the equation to calculate f(-2)

f(-2) = (3/2)(-2) - 2

= -3 -2

= -5

Thus, your answer is A.

Have an awesome day! :)
4 0
3 years ago
The functions $f$ and $g$ are defined as follows: \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\quad\text{and}\quad g(x) = \dfrac{\sqrt{x+1}}
AlladinOne [14]

Recall that √x has a domain of x ≥ 0.

So, f(x) is defined as long as

(x + 1)/(x - 1) ≥ 0

• We have equality when x = -1

• Otherwise (x + 1)/(x - 1) is positive if both x + 1 and x - 1 are positive, or both are negative:

\begin{cases}x+1>0 \implies x>-1 \\ x-1>0 \implies x>1\end{cases} \implies x > 1

\begin{cases}x+1

Then the domain of f(x) is

x > 1   or   x ≤ -1

On the other hand, g(x) is defined by two individual square root expressions with respective domains of

• x + 1 ≥ 0   ⇒   x ≥ -1

• x - 1 ≥ 0   ⇒   x ≥ 1

but note that g(1) is undefined, so we omit it from the second domain.

Then g(x) is defined so long as both x ≥ -1 *and* x > 1 are satisfied, which means its domain is

x > 1

f(x) and g(x) have different domains, so they are not the same function.

4 0
2 years ago
What are some strategies to develop a growth mindset?
Serga [27]

Answer:

Focusing on your academic studies

Explanation:

4 0
2 years ago
Read 2 more answers
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