The length is 8 and the width is 4
P = L + L + W + W
P = 8 + 8 + 4 + 4
P = 16 + 4 + 4
P = 16 + 8
P = 24
I am an organized person, so i make a checklist of all my notes and study them in order and that helps me a lot for the EOGs
The answer is “No” because the line is not proportional.
In this question, you are asked the probability for any of the 30 person to have the same birthday. To answer this it will be easier to calculate how much the probability for no one has same birthday. Let say the first person birthday is 1. Then the next person birthday should be other than 1, which mean 364 possible days out of 365 days. The next person should be 363 possible days out of 365 days
Then the calculation for 30 people would be:
(365!/365-30!)/(365^(30)= (365!/335!)/ 365^30= 29.4%
Then the probability of at least two person have same birthday would be: 100%-29.4%= 70.6%
Answer:
47.36
Step-by-step explanation:
i did the work
