3 years ago

How do i get y alone when (–3)-3y=0

Mathematics

2 answers:

katen-ka-za [31]3 years ago

7 0

-3-3y=0
+3 +3
_________
-3y = 3
__ __
-3 -3

y = -1

kotykmax [81]3 years ago

7 0

You do inverse operations to get the y alone so for the -3-3y=0 you would to +3 to the 0 so the equation is now -3y=3 now from here you do 3 divide by -3 which is -1 so no your answer is y=-1

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Solve the Quadratic Equation By Completing the Square b^2-15b-54=0

vladimir1956 [14]

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b^{2}-15b=54. \newline
b^{2}-15b+(\frac{15}{2})^{2}=54+(\frac{15}{2})^{2}. \newline
(b-\frac{15}{2})^{2}=\frac{441}{4}. \newline
b-\frac{15}{2}=\pm\frac{21}{2}. \newline
b=\pm\frac{21}{2}+\frac{15}{2}. \newline
b_1 = -3, b_2 = 18.$