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2 years ago

A biologist tracked the growth of a stain of bacteria, as shown in the graph.

Mathematics

1 answer:

Alisiya [41]2 years ago

3 0

98+876=864 sheepcot I am so happy for that your so

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If m< BOE = 130 degrees and m< cob = 80 degrees

hjlf

Answer:

then what?

Step-by-step explanation:

do we have to find the angle?

all I know is every right triangle is equal to 90°

6 0

3 years ago

Audryn left a $12 tip on a $68.73 restaurant bill. What percent tip did she leave? Round to the nearest tenth of a percent.

Fiesta28 [93]

So, if we take 68.73 to be the 100%, what is 12 in percentage off of it?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
68.73&100\\
12&p
\end{array}\implies \cfrac{68.73}{12}=\cfrac{100}{p}\implies p=\cfrac{12\cdot 100}{68.73}$

seems Audryn is being generous, she probably got the silverware and the maple leaves tablecloth.

4 0

3 years ago

A circle in the xy plane has a center at (3/4, 1/2)

Leokris [45]

Answer:

(x - 3/4)^2 + (y - 1/2)^2 = r^2

<em>Brainliest, please!</em>

Step-by-step explanation:

Equation of a circle: (x - h)^2 + (y - k)^2 = r^2

(x - 3/4)^2 + (y - 1/2)^2 = r^2

We do not have enough information to find the radius. Were you given another point that lies on the circle?

3 0

3 years ago

Suppose a package delivery company purchased 14 trucks at the same time. Five trucks were purchased from manufacturer A, four fr

nikklg [1K]

Answer:

Step-by-step explanation:

Given that a package delivery company purchased 14 trucks at the same time. Five trucks were purchased from manufacturer A, four from manufacturer B, and five from manufacturer C. The cost of maintaining each truck was recorded.

No of companies = 3

No of items in total = 14

Total df = 17-1=16

degrees of freedom between groups = 3-1 =2

Hence degrees of freedom for denominator

= $16-2 =14$

5 0

3 years ago

Find the exact value

ivann1987 [24]

Answer:

Step-by-step explanation:

$cos~ \theta=\sqrt{1-sin^2 \theta} =\sqrt{1-(\frac{1}{2})^2 } =\frac{\sqrt{3} }{2} \\1+cos~\theta=2cos^2\frac{\theta}{2} \\1+\frac{\sqrt{3}}{2} =2~cos^2 \frac{\theta}{2} \\cos^2\frac{\theta}{2} =\frac{2+\sqrt{3}}{2 \times 2} \\cos \frac{\theta}{2} =\frac{\sqrt{2+\sqrt{3}}}{2} \\1-cos \theta=2 ~sin^2\frac{\theta}{2} \\1-\frac{\sqrt{3}}{2}=2~sin^2 \frac{\theta}{2} \\sin^2 \frac{\theta}{2} =\frac{2-\sqrt{3} }{2 \times 2} \\sin \frac{\theta}{2}=\frac{\sqrt{2-\sqrt{3} } }{2}$

as 0≤θ≤90

so θ/2 is also in 0≤θ≤90

hence sin θ/2 and cos θ/2 are positive.

3 0

2 years ago