Answer:
The estimated probability that Ginger will eat a a pizza everyday of the week is;
D. 8/10 = 80%
Step-by-step explanation:
The given parameters are;
The frequency with which Ginger buys launch = Everyday
The percentage of the time the cafeteria has pizza out = 80%
The outcome of 0 and 1 = No pizza available
The outcome of 2, 3, 4, 5, 6, 7, 8, and 9 = Pizza available
Therefore, we have the;
Group number
Percentage of time pizza available
1
80%
2
80%
3
80%
4
80%
5
40%
6
100%
7
80%
8
100%
9
80%
10
80%
Therefore, the sum of the percentages outcome the days Ginger eats pizza = 0.8 + 0.8 + 0.8 + 0.8 + 0.4 + 1 + 0.8 + 1 + 0.8 + 0.8 = 8
The number of runs of simulation = 10 runs
The estimated probability that Ginger will eat a a pizza everyday of the week = (The sum of the percentages outcome the days Ginger eats pizza)/(The number of runs of simulation)
∴ The estimated probability that Ginger will eat a a pizza everyday of the week = 8/10
4÷631=157.75 hope that helps ya!!!!
Answer:
= .0000001
Step-by-step explanation:
The odds of getting 1 number of out the 10 possible number (0-9) equal 10 is 1/10
There are 7 numbers to pick
P(xxx-xxxx) = 1/10 * 1/10 *1/10 * 1/10 * 1/10 * 1/10 *1/10
= .0000001
To make the pattern it only uses a horizontal translation and a 180 rotation, so the second one.
Hope this helps.