The tangent line is perpendicular to the radius, so will have slope
.. -1/2.5 = -0.4 . . . . . . corresponding to the 3rd selection
Set each factor equal to 0
4x-3 = 0
2x-1 = 0
Solve for x.
4x-3=0
4x=3
x= 3/4
Solve for x.
2x-1= 0
2x= 1
x= 1/2
Eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x
<span>RhombusP diagonal is = 8cmQ diagonals = 10cmArea of rhombus = p. q/28 .10/2 =80 / 2 = 40 cm
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A slope of 3/2 passing through (-3,0) gives us slope intercept form of
y - 0 = (3/2) (x - -3)
y = (3/2) x + 9/2
That's a y intercect of 9/2
Choice D
The value of x and y based on the equation will be 3 2/3 and 4 respectively.
<h3>How to compute the values?</h3>
The equation given in the question is represented below:
x/5 + y/3 = 3 ..... equation i
3x - 2y = 3 ...... equation ii
Equation i can be rewritten as 3x + 5y = 15
The equations will be:
3x + 5y = 15
3x - 2y = 3
Subtract equation ii from i
3y = 12
Divide both side by 3
3y/3 = 12/3
y = 4
Put y = 4 into equation ii
3x - 2y = 3
3x - 2(4) = 3
3x - 8 = 3
3x = 3 + 8
3x = 11
x = 11/3 = 3 2/3
Therefore, the value of x and y based on the equation will be 3 2/3 and 4 respectively.
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