Given:
The inequality is:
To find:
The graph of the given inequality.
Solution:
We have,
Subtract both sides by 1.
Divide both sides by 3.
The value of t is less than or equal to 
.
Since , it means is included in the solution, therefore there is a closed circle at 
and an arrow approaches to left from .
Therefore, the correct option is A.
Answer:
a) 2.5
b) 6.25
Step-by-step explanation:
For similar figures, the ratio of any corresponding linear dimensions is the same. The ratio of areas is the square of that.
<h3>Application</h3>
The ratio of linear dimensions, larger to smaller, is ...
(30 yd)/(12 yd) = 2.5
<h3>a) Perimeter</h3>
Perimeter is a linear dimension, the sum of side lengths. The ratio of perimeters is 2.5.
<h3>b) Area</h3>
The ratio of areas, larger to smaller, is the square of the scale factor for side lengths:
(2.5)² = 6.25
The ratio of the areas of the larger to smaller figure is 6.25.
Well you would start at Y= 0(-x) -2. So (0, -2) then you would move to the left by 1 and move down by 1.
A. The distance between the red ant and the black ant is five units.
To represent the red ant,
xr = 3 - t
yr = 2 + 2 t
zr = 6 + 2 t
To represent the black ant,
xb = t/2
yb = 2 + 3 t
zb = 2 + t
To calculate,
at t = 0
xb - xr = -3
yb - yr - 2-2 = 0
zb - zr = 2-6 = -4
Therefore,
d = √(9+16) = √(25) = 5
b. There will be no collision between the two ants.
To calculate,
3 - t = t/2
6 - 2t = t
6 = 3t
t = 2
If t = 2,
2 + 2*2 = 2 + 3*2
Answer:
Explanation:
The figure labeled A cannot be because the cross and the line are not oriented in the same relative position as in X.
The figure labeled B cannot be because the line and the the image with the three lines are not oriented in the same relative position as in X.
You cannot tell about the figures labeled C because you do not see the images of the cross and the line.
The figure labeled E cannot be because the image with the three lines is not oriented in the same relative positiion with respect to the other two as in X.
You cannot tell about the figure labeled F because the image of the cross and with the three lines are not shown.
The figure labeled G is correct: you can just rotate the cube labeled X 90 degrees counterclockwise about a vertical axis that passes through the center of the cube and get the cube labeled G.
