Hello,
y=8/6 x-40/6
==>rate=8/6=4/3
2a) if 1 ft³ weighs 150 lb==>the TOTAL VOLUME =5,000/150 =33.334 ft³
2b) 1 ft³ 1,728 in³. So the TOTAL volume in in³ =33.334 x 1728 = 57,600 in³
c) Volume =(1/3)(πR²).H but R = H then V= (1/3)(πR³).plug V (=57600)
57,600 = 1/3 (πR³) ==> R³ = (3 x 57600) / π ==> R = 38 in
d) Area x thickness = Volume ==> Area x 2 in = 57600 in then:
Are =57600/2 & Area =28,800 in²
Answer:
x=3
Step-by-step explanation:
Vertical angles are equal so
<A = <B
7x+2 = 4x+11
Subtract 4x from each side
7x+2-4x = 4x+11-4x
3x+2 =11
Subtract 2 from each side
3x+2-2 = 11-2
3x = 9
Divide by 3
3x/3 = 9/3
x=3
NOT MY WORDS TAKEN FROM A SOURCE!
(x^2) <64 => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2 so (x^2) - (8^2) < 0 To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y) You can work backwards and verify this is true. so let's set (x^2) - (8^2) equal to zero to find the roots: (x^2) - (8^2) = 0 => (x-8)*(x+8) = 0 if x-8 = 0 => x=8 and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0 so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0 so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0 so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.
Hope this helped!
:)
The answer is 1)B 2)C 3)F