Answer:
(x+3)(x+2)
Step-by-step explanation:
take x^2 and take it apart. so it should be (x+ ) (x+ ) then take 6 and make it so it's multipuls equal 5. ur answer should be (x+3)(x+2) or vice versa.
Sixty-nine thousand, a hundred and eight?
The x value when everything is solved or when the all of the x's are combined?
Answer:
The first equation; x-2y=8
Step-by-step explanation:
Hi there!
We're told that Ty wants to isolate x in one of the equations. To do so in either, he will need to use inverse operations to cancel out values and leave just x remaining on one side of the equation.
In the second equation, he would need to subtract both sides by 6y and then divide both sides by 4 to isolate x. It's a two-step process.
However, in the first equation, he only needs to add 2y to both sides to isolate x.
I hope this helps!
<span><span>let x = cows last year
</span>
</span><span><span>let y = bulls last year
</span>
</span><span><span>x + y = last years total
</span>
</span><span><span>0.9x + 1.5y = 660 (this year's total)
</span>
<span>1.1(x+y) = 660 </span>= </span><span>1.1x + 1.1y = 660
</span><span>
</span><span><span>so:
</span>
</span><span><span>0.9x + 1.5y = 1.1x + 1.1y
</span>
</span><span><span>subtract 0.9x from each side:
</span>
</span><span><span>1.5y = 0.2x + 1.1y
</span>
</span><span><span>subtract 1.1y from each side
</span>
</span><span><span>0.4y = 0.2x
</span>
</span><span><span>to make x 1 multiply both sides by 5
</span>
</span><span><span>2y = x
</span>
</span><span><span>substitute for x in one of the original problems:
</span>
since they had 660 this year and that number is 10%
higher than last year, then we had 600 total last year. </span>
<span><span>So:
</span>
</span><span><span>600 = x + y
</span>
</span><span><span>substitute into that one with the 2y = x
</span>
</span><span><span>600 = 2y + y
</span>
</span><span><span>600 = 3y
</span>
</span><span><span>200 = y
</span>
</span><span><span>then 600 - y = x
</span>
</span><span><span>so 600 - 200 = x
</span>
400 = x</span>
<span> So you had 400 cows and 200 bulls last year</span>
