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Ratling [72]
3 years ago
11

Simplify the problem thank you

Mathematics
2 answers:
never [62]3 years ago
8 0

Answer:

-5

Step-by-step explanation:

(-5)(-5)(-5)=-125

NikAS [45]3 years ago
5 0

Given the expression:

\displaystyle \large{ \sqrt[3]{ - 125} }

Definition:

\displaystyle \large{ y  = \begin{cases}   \pm \sqrt[n]{x}  \longrightarrow n  = (2,4,6,8,...)  \:  \: (x \geqslant 0) \\   \sqrt[n]{x}\longrightarrow n = (1,3,5,7,...) \:  \: (x \in \R) \end{cases}}

First, factor the -125. -125 comes from (-5)×(-5)×(-5) or (-5)^3.

\displaystyle \large{ \sqrt[3]{ ( - 5) \times ( - 5) \times ( - 5)} }

Because if (-5)^2 = 25 then 25×(-5) again will be -125.

Since this is the cube root, we have to pull out 3 terms in one. There are 3 fives that we can take off and therefore,

\displaystyle \large \boxed{ - 5}

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Given that 2y^3+by-cy+d,where b,c and d are constants,leaves a remainder R when divided by (y+1) , (y-2) and (2y-1). Find the va
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<em />

We're also given that <em>y</em> + 2 is a factor, which means dividing <em>p(y)</em> by it leaves no remainder, and so

<em>p</em>(-2) = 2(-2)³ + <em>b</em>(-2)² - <em>c</em>(-2) + <em>d</em> = 0

==>  0 = -16 + 4<em>b</em> + 2<em>c</em> + <em>d</em>

<em />

Solve the system of equations in boldface. You can eliminate <em>d</em> from the first 3 to first solve for <em>b</em> and <em>c</em>, then solve for <em>d</em> :

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