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Ratling [72]
3 years ago
11

Simplify the problem thank you

Mathematics
2 answers:
never [62]3 years ago
8 0

Answer:

-5

Step-by-step explanation:

(-5)(-5)(-5)=-125

NikAS [45]3 years ago
5 0

Given the expression:

\displaystyle \large{ \sqrt[3]{ - 125} }

Definition:

\displaystyle \large{ y  = \begin{cases}   \pm \sqrt[n]{x}  \longrightarrow n  = (2,4,6,8,...)  \:  \: (x \geqslant 0) \\   \sqrt[n]{x}\longrightarrow n = (1,3,5,7,...) \:  \: (x \in \R) \end{cases}}

First, factor the -125. -125 comes from (-5)×(-5)×(-5) or (-5)^3.

\displaystyle \large{ \sqrt[3]{ ( - 5) \times ( - 5) \times ( - 5)} }

Because if (-5)^2 = 25 then 25×(-5) again will be -125.

Since this is the cube root, we have to pull out 3 terms in one. There are 3 fives that we can take off and therefore,

\displaystyle \large \boxed{ - 5}

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Find all pairs of natural numbers which can be the solution to the equation a+b=42.
Setler [38]

Answer:

(1,41), (2,40), (3,39), (4,38), (5,37), (6,36), (7,35), (8,34), (9,33), (10,32), (11,31), (12,30), (13,29), (14,28), (15,27), (16,26), (17,25), (18,24), (19,23), (20,22), (21,21), (22,20), (23,19), (24,18), (25,17), (26,16), (27,15), (28,14), (29,13), (30,12), (31,11), (32,10), (33,9), (34,8), (35,7), (36,6), (37,5), (38,4), (39,3), (40,2), (41,1).

Step-by-step explanation:

To find all pairs of natural numbers which are solution to a+b=42, we need to first choose a value to one of them (let's choose 'a'), and that value will be the lowest possible, so we begin with a=1, and then we increase to 2, and 3, and so on.

For each value of a, we calculate the value of b using the equation.

So, starting with a=1, we have that b=41

Then, with a=2, we have that b=40, and so on.

Doing this until a=41 (so b=1 will be the lowest value possible for b), we have the pairs of natural number we want:

(1,41), (2,40), (3,39), (4,38), (5,37), (6,36), (7,35), (8,34), (9,33), (10,32), (11,31), (12,30), (13,29), (14,28), (15,27), (16,26), (17,25), (18,24), (19,23), (20,22), (21,21), (22,20), (23,19), (24,18), (25,17), (26,16), (27,15), (28,14), (29,13), (30,12), (31,11), (32,10), (33,9), (34,8), (35,7), (36,6), (37,5), (38,4), (39,3), (40,2), (41,1).

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