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ladessa [460]
2 years ago
9

Please help me with this math problem!! NO LINKS PLEASE!! :)

Mathematics
1 answer:
earnstyle [38]2 years ago
8 0

Answer:

105°.

Step-by-step explanation:

1) to calculate m(∠ABC): m(∠ABC)=180-m(∠BAC)-m(∠(ACB)=180-90-65=25°;

2) note, m(∠ABC)=m∠(ABD)=25°, then it is possible

3) to calculate m(∠BAD): m(∠BAD)=180-m(∠ABD)-m(∠ADB)=180-25-50=105°.

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Without using calculator or table find the value of sin 15°​
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Answer:

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Step-by-step explanation:

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Nicole runs a farm stand that sells bananas and peaches. Each pound of bananas sells for $2 and each pound of peaches sells for
stepan [7]

<u><em>Answer:</em></u>

<u>The required system of equations is:</u>

2x + 3.25y = 231.75

x = y + 3

where x is the number of pounds of bananas and y is the number of pounds of peaches

<u><em>Explanation:</em></u>

<u>1- Defining the variables:</u>

Assume that the number of pounds of bananas sold is x

Assume that the number of pounds of peaches sold is y

<u>2- Setting the system of equations:</u>

<u>We are given that:</u>

i. Each pound of bananas sells for $2

  Money gained from selling x pounds of bananas is 2x

ii. Each pound of peach sells for $3.23

   Money gained from selling y pounds of peaches is 3.25y

iii. Nicole made $231.75 in total. <u>This means that:</u>

    2x + 3.25y = 231.75 .................> equation I

iv. Nicole sold 3 more pounds of bananas than pounds of peaches. <u>This</u>

    <u>means that:</u>

    pounds of bananas = pounds of peaches + 3

    x = y + 3 ..................> equation II

<u>3- Solving the equations (if required):</u>

In equation II, we have: x = y + 3

<u>Substitute with equation II in equation I and solve for y as follows:</u>

2x + 3.25y = 231.75

2(y+3) + 3.25y = 231.75

2y + 6 + 3.25y = 231.75

5.25y = 231.75 - 6

5.25y = 225.75

y = 43

<u>Substitute with y in equation II to get x:</u>

x = y + 3

x = 43 + 3 = 46

<u>Based on the above:</u>

Number of pounds of bananas = x = 46 pounds

Number of pounds of peaches = y = 43 pounds

Hope this helps :)

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The median of the set data set is 4
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