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alexgriva [62]
2 years ago
15

Please help me find answer. midpoints invloved

Mathematics
2 answers:
Nimfa-mama [501]2 years ago
7 0

Answer:

7x - 12 = 3x - 2

Step-by-step explanation:

katrin2010 [14]2 years ago
4 0

the answer is A) 8

Step-by-step explanation:

if that the midpoint, so 7x -12 = 2(3x-2)

do the equation and you can get x=8

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We would do, 4×2 = 8.

8 - 2 = 6.

Sense 6 is the amount of how much -4 and +2 would be from each other, this would then mean that x would then equal 8.

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Circle A was dilated with the origin as the center of dilation to creat circle b
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Find the equation of a line that is parallel to the line y=7 and contains the point (1,-3)
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Use the given graph of f to estimate the intervals on which the derivative f ' is increasing or decreasing. (Enter your answers
NARA [144]

The derivative of a function is used to determine whether the function is increasing or decreasing on any intervals in its domain.

Derivative of function f is increasing in interval  (-2 , 1) and (3 , 6)

Derivative of function f is decreasing in interval (1 , 3) and (6 , 9)

If f′(x) > 0 at each point in an interval , then the function is said to be increasing in that interval.

If f′(x) < 0 at each point in an interval , then the function is said to be decreasing on that interval.

By observing graph, it is observed that slope  of function f is positive in interval  (-2 , 1) and (3 , 6) . Hence, derivative of  function f is increasing in interval  (-2 , 1) and (3 , 6)

By observing graph, it is observed that slope  of function f is negative in interval  (1 , 3) and (6 , 9) . Hence, derivative of  function f is decreasing in interval  (1 , 3) and (6 , 9).

Learn more:

brainly.com/question/14330051

5 0
2 years ago
For each of the systems of equations that follow, use Gaussian elimination to obtain an equivalent system whose coefficient matr
noname [10]

Answer:

b) inconsistent

d) inconsistent

f) inconsistent

j) X_1 = 2 - 6a , X_2 = 4 + a , X_3 = 3 - a, X_4 = a (free variable)

Step-by-step explanation:

b)

Given: Augmented matrix

\left[\begin{array}{ccc}2&-3&5\\-4&6&8\end{array}\right]

Row operation : R_2 + 2*R_1

\left[\begin{array}{ccc}2&-3&5\\0&0&18\end{array}\right]

Looking at R_2 : 0 not equal to 18 ; Hence, inconsistent

c)

Given: Augmented matrix

\left[\begin{array}{cccc}3&2&-3&4\\1&-2&2&1\\11&2&1&14\end{array}\right]

Row operation : R_2 <---> R_1

\left[\begin{array}{cccc}1&-2&2&1\\3&2&-3&4\\11&2&1&14\end{array}\right]\\

Row operations : R_2 - 3*R_1   &   R_3 - 11*R_1

\left[\begin{array}{cccc}1&-2&2&1\\0&8&-9&1\\0&24&-21&3\end{array}\right]\\

Row operations : R_3 - 3*R_2  

\left[\begin{array}{cccc}1&-2&2&1\\0&8&-9&1\\0&0&6&0\end{array}\right]\\

Looking at R_3 : 0 not equal to 6 ; Hence, inconsistent

f)

Given: Augmented matrix

\left[\begin{array}{cccc}1&-1&2&4\\2&3&-1&1\\7&3&4&7\end{array}\right]\\

Row operations : R_2 - 2*R_1   &   R_3 - 7*R_1

\left[\begin{array}{cccc}1&-1&2&4\\0&5&-5&-7\\0&10&-10&-21\end{array}\right]\\

Row operations : R_2 --> ( 1 / 5 )* R_2  & R_3 --> ( 1 / 10 )* R_3

\left[\begin{array}{cccc}1&-1&2&4\\0&1&-1&-1.4\\0&1&-1&-2.1\end{array}\right]\\

Row operations : R_3 - R_1

\left[\begin{array}{cccc}1&-1&2&4\\0&1&-1&-1.4\\0&0&0&-0.7\end{array}\right]\\

Looking at R_3 : 0 not equal to -0.7 ; Hence, inconsistent

j)

Given: Augmented matrix

\left[\begin{array}{ccccc}1&2&-3&1&1\\-1&-1&4&-1&6\\-2&-4&7&-1&1\end{array}\right]\\

Row operations : R_2 + R_1   &   R_3 + 2*R_1

\left[\begin{array}{ccccc}1&2&-3&1&1\\0&1&1&0&7\\0&0&1&1&3\end{array}\right]\\

corresponding equations are:

X_1 + 2*X_2 - 3*X_3 + X_4 = 1

X_2 + X_3  = 7

X_3 + X_4 = 3

Free parameter : X_4 = a , then:

X_3 = 3 - a

X_2 = 4 + a

X_1 = 1 - a + 3*(3 - a) - 2*(4 + a) = 2 - 6 a

4 0
4 years ago
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