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kkurt [141]
3 years ago
9

Quadratic formula for 2x^2-x-3=0

Mathematics
2 answers:
Inessa [10]3 years ago
8 0
Ax^2+bx+c=0
a=2
b=-1
c=-3
b+-sqrt( b^2 - 4ac)
          2a

so...
-1 +- sqrt(1 + 24)
           4
-1 +- 5
    4
x= -1 + 5 = 1
         4
or
x= -1 - 5 = -3/2
         4
pychu [463]3 years ago
6 0
x=1x⁺₋√-1x²-4*2x^2*-3/2(2x^2
This is the equation.

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A pie is cut into 9 equal pieces. If all but 3 pieces are eaten, how of the pie remains?
Vadim26 [7]

Answer:

1/3 or 3

Step-by-step explanation:

9-6 = 3

6 0
4 years ago
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What is the value of x in the equation 2.5x+ 10 = x- 0.5
Amiraneli [1.4K]
The value of x is -7
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Danny is building a pyramid modeled after one of the great pyramids of Giza in Egypt .The great pyramid has a height of 480 feet
Licemer1 [7]

Answer:

91.204 cubic feet

Step-by-step explanation:

We are given that

Height of great pyramid, h=480feet

Side of square base, a=755  feet

Height of Danny's pyramid, h'=480/100 feet

Side of square base of Danny's pyramid, a'=755/100 feet

We have to find the volume of Danny's pyramid if the volume of Danny's pyramid is 1/100 the size of great pyramid.

We know that

Volume of square base pyramid, V=\frac{1}{3}a^2h

Where a= Side of base

h=Height of pyramid

Using the formula

Volume of Danny's pyramid=\frac{1}{3}\times(755/100)^2(480/100)ft^3

Volume of Danny's pyramid=91.204 cubic feet

7 0
3 years ago
A group of students wish to go bowling. There is a flat rate of $5 per student for shoe rental. It then costs $2.50 per
Andreyy89

Answer:

i am on the same one T-T

Step-by-step explanation:

3 0
3 years ago
At an airport, 79% of recent flights have arrived on time. A sample of 7flights is studied. a.Compute the mean of this probabili
xxTIMURxx [149]

Answer:

a. 5.53

b. 1.078

c. 0.126

d. 0.109

e. 0.549

f. 0.834

g.  0.451

Step-by-step explanation:

The percentage of the flights that arrive on time, P(x) = 79%

The number of flights in the sample, n = 7 flights

a. The mean of the probability distribution, μ = ∑x·P(x)

Therefore, we have; μₓ = n·p

μₓ = 7 × 79/100 = 5.53

b. The standard deviation, σₓ = √(n·p·(1 - p))

∴ σₓ = √(7 × 0.79 × (1 - 0.79)) ≈ 1.078

c. We have;

p = 0.79

q = 1 - p = 1 - 0.79 = 0.21

By binomial probability distribution formula, we have;

The probability of exactly four, P(Exactly 4) = ₇C₄·p⁴·q³

P(Exactly 4) = 35 × 0.79⁴×0.21³ ≈ 0.12625

d. The probability of less than 4 is given as follows;

P(Less than 4) = ₇C₀·p⁰·q⁷ + ₇C₁·p¹·q⁶ + ₇C₂·p²·q⁵ + ₇C₃·p³·q⁴

∴ P(Less than 4) = 1×0.79^0 * 0.21^7 + 7 * 0.79^1 × 0.21^6 + 21*0.79^2*0.29^5+ 85×0.79^3*0.21^4 ≈ 0.109

The probability of less than 4 is ≈ 0.109

e. The probability that more than 5 is given as follows;

P(More than 5) = ₇C₆·p⁶·q¹ + ₇C₇·p⁷·q⁰

7×0.79^6 * 0.21 + 1 * 0.79^7 × 0.21^0 ≈ 0.549

f. The probability that at least 5 of the flight were on time is given as follows;

P(At least 5) = ₇C₅·p⁵·q² + ₇C₆·p⁶·q¹ + ₇C₇·p⁷·q⁰

∴ P(At least 5) = 21×0.79^5 * 0.21^2 + 7×0.79^6 * 0.21 + 1 * 0.79^7 × 0.21^0 ≈ 0.834

g.  For the probability that no more than 5 of the flights were on time, e have;

P(At most 5) = 1 - P(More than 5)

∴ P(At most 5) = 1 - 0.549 ≈ 0.451.

6 0
3 years ago
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