Answer:
Jaya can afford to rent a car 4 days while staying within her budget.
Step-by-step explanation:
The inequality would have to indicate that the cost of renting a car has to be less than or equal to $230. The cost to rent a car is equal to the cost per day for the number of days plus the price per mile for the number of miles, which is:
53.75x+0.12y≤230, where:
x is the number of days the car is rented
y is the number of miles driven
As the statement says that she plans to drive 125 miles, you can replace "y" with this value and solve for x:
53.75x+0.12(125)≤230
53.75x+15≤230
53.75x≤230-15
53.75x≤215
x≤215/53.75
x≤4
According to this, the answer is that Jaya can afford to rent a car 4 days while staying within her budget.
Answer:
31
Step-by-step explanation:
25% of the students like football
Answer:
the first answer is correct
the second answer is correct if they messed up on the question and meant to ask for the MAD of set B
I think the 3rd answer is incorrect (I got 1.09), so you might want to double-check your 3rd answer since it is asking for "times bigger", not how much bigger, which means how many times larger is the MAD of set A than that of set B and to find how many times bigger a number is than another number, you have to divide the first number by the second number.
Step-by-step explanation:
Answer:
1 solution
Step-by-step explanation:
Jeremy can simplify the equation enough to determine if the x-coefficient on one side of the equation is the same or different from the x-coefficient on the other side. Here, that simplification is ...
-3x -3 +3x = -3x +3 +3
We see that the x-coefficient on the left is 0; on the right, it is -3. These values are different, so there is one solution.
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In the attached, the left-side expression is called y1; the right-side expression is called y2. The two expressions are equal where the lines they represent intersect. That point of intersection is x=3. (For that value of x, both sides of the equation have a value of -3.)
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<em>Additional comment</em>
If the equation's x-coefficients were the same, we'd have to look at the constants. If they're the same, there are an infinite number of solutions. If they are different, there are no solutions.