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Shkiper50 [21]
3 years ago
11

Can somebody help me as soon as possible I’ll give brainliest

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
4 0
Hi hi hi hi hi hi hi hi hi hi hi hi hi
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Rochelle is 1.75 meters tall. Evan is 12 centimeters taller. How tall is Evan in centimeters ?
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787cm tall than Rochelle
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What is the value of the expression “two less than six times the difference of a number and five” when n = 9?
Finger [1]

Answer:

Try solving 6(n-5)-2.

Step-by-step explanation:

I believe this can be set up as 6(n-5)-2. The difference of a number and five can be represented by n-5. If this needs to be multiplied by 6 (hence 6 times), it would become 6(n-5). Two less than that is represented by -2. Thus, two less than six times the difference of a number and five is 6(n-5) -2, which, when n=9 is plugged in, looks like 6(9-5) -2. Follow PEMDAS from there.

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3 years ago
A car dealership is comparing the sales of two employees. The equation that represents Kevin’s sales is S = 60n-5, where n repre
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I been trying to look for that answer for so long but can we help each other at least

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3 years ago
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An article reports "attendance dropped 2% this year, to 5053." What was the attendance before the drop? (Round your answer to th
Shalnov [3]

Answer:

5156

Step-by-step explanation:

Let x represent the initial attendance;

Since the initial attendance dropped by 2%

New attendance = x - 2% of x = x - 0.02x

New attendance = 0.98x

Given;

New attendance = 5053

Equating the values and solving for x;

0.98x = 5053

x = 5053/0.98

x = 5156.12

x = 5156

Initial attendance before the drop = 5156

8 0
4 years ago
4. Complete the table given below
DIA [1.3K]

To solve this formula, we can simply use the formula of half-life of a radioactive substance to calculate the decay rate.

The disintegration constant or decay rate is calculated as 0.385min^-1

<h3>Half-Life</h3>

The half-life of a radioactive substance is defined as the time taken for the initial mass of the substance to reach half it's starting mass.

The formula is given as

T_\frac{1}{2} = \frac{\ln2}{\lambda}

Let's substitute the value into the equation and solve through

T_\frac{1}{2} = \frac{\ln2}{\lambda} \\\lambda = \frac{\ln2}{T_\frac{1}{2} } \\\lambda = \frac{0.693}{1.8} \\\lambda = 0.385

The disintegration constant or decay rate is calculated as 0.385min^-1

Learn more on half-life here;

brainly.com/question/26148784

#SPJ1

5 0
2 years ago
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