Answer:
A. replace the network cable
Explanation:
Based on the information provided within the question it can be said that in this scenario the best option would be to replace the network cable. The network cable refers to the Ethernet cable that is connected to the individuals personal computer. This cable being faulty is most likely the reason as too why the individual is not able to connect. Since it is displaying that signals return too early it means that there is most likely information being lost in transit.
int sum = 0;
int number;
for (int i=0; i<10; i++) {
printf("Enter an integer number: ");
scanf_s("%d", &number);
sum += number;
}
printf("The sum is %d", sum);
Answer:
<u>Advantages of wireless communication:-</u>
- Flexibility in transferring the message through communication for which the sender and receiver can be in any place.
- Speed of the communication is accurate and fast
- Due to no wiring , the cost of the wireless communication is less.
<u>Disadvantages of wireless communication:-</u>
- The security is less as the data can be accessed by unauthorized sources at times.
- The setting up of wireless communication complex and expensive.
<u>Advantages of wired communication:-</u>
- Simple configuration
- Higher bandwidth is present in the cable
- High reliability
<u>Disadvantages of wired communication:-</u>
- Mobility is present for communication
- Installation requires lot of time due to cabling
- Requires extra devices for covering large areas for communication
Wireless communication is more preferable than wired communication in the conditions like communication connection that should face low damage and longer life which is not present in cable connection as they break or get disrupted.The flexibility of moving while communication is required by most people so, they use wireless communication .
Answer:
a. 118.20.210.254
Explanation:
Here are the few characteristics of Class A:
First bit of the first octet of class A is 0.
This class has 8 bits for network and 24 bits for hosts.
The default sub-net mask for class A IP address is 255.0.0.0
Lets see if the first bit of first octet of 118.20.210.254 address is 0.
118 in binary (8 bits) can be represented as : 1110110
To complete 8 bits add a 0 to the left.
01110110
First bit of the first octet of class A is 0 So this is class A address.
For option b the first octet is : 183 in the form of bits = 10110111 So it is not class A address
For option c the first octet is 215 in the form of bits = 11010111 So it is not class A address
For option d the first octet is 255 in the form of bits = 11111111. The first bit of first octet is not 0 so it is also not class A address.