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mote1985 [20]
2 years ago
13

PLEASE HELP -7y + 11 = 75 + y

Mathematics
1 answer:
Masja [62]2 years ago
3 0

Answer:

y = -8

Step-by-step explanation:

-7y + 11 = 75 + y

Bring the <em>"</em><em>y</em><em>"</em><em> </em>variable on one side, and rest on the other.

Rearranging, we get,

-7y - y = 75 - 11

-8y = 64

-y = 8

y = -8

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>

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According to this diagram, what is cos 28°? 62° 17 8 28° 90° 15 O A. 17 15 O B. 8 17 O c. 15 17 O D. O E. 8 15 15 OF.​
VikaD [51]

Answer:

C. Cos(28) = \frac{15}{17}

Step-by-step explanation:

Recall: SOHCAHTOA

Thus,

Cos(\theta) = \frac{Adjacent}{Hypotenuse}

Reference angle = 28°

Adjacent = 15

Hypotenuse = 17

Plug in the values

Cos(28) = \frac{15}{17}

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3 years ago
If q→ p is true, then ~ p → ~ q is _____ true. always sometimes never
Bogdan [553]

Answer: always

Step-by-step explanation:

6 0
3 years ago
F (x) = –2x+1<br> If<br> f (x) = 11<br> Find the value of x:
a_sh-v [17]

Answer:

Now x is equals to 11

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The answer is - 21

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8 0
2 years ago
Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

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3 years ago
I have 453 grams of strawberries I have 23 grams left how many grams of strawberries are left
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