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2 years ago

Find the 7th term of the arithmetic sequence 4x + 5, 11x + 9,18x + 13, ...

Mathematics

1 answer:

Svet_ta [14]2 years ago

5 0

Step-by-step explanation:

we see the common difference is

a2-a1 = 11x + 9 - 4x - 5 = 7x + 4

an = an-1 + (7x+4) = a1 + (n-1)×(7x+4)

for a7 we have then

a7 = 4x + 5 + 6×(7x +4) = 4x + 5 + 42x + 24 = 46x + 29

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Find the slope of the line(s) passing through the given points. Then tell whether the line(s) rises, falls, is horizontal, or is

bonufazy [111]

Answer:

21) falls

22) vertical

23) rises

24) rises

25) falls

26) horizontal

27) rises

28) horizontal

29) falls

Step-by-step explanation:

We shall use the slope formula $m=\frac{y_2-y_1}{x_2-x_1}$ to calculate the slopes of the line passing through each pair of point.

21: (3,1), (2,6)

The slope is $m=\frac{6-1}{2-3}$

$\implies m=\frac{5}{-1}=-5$ .

A negative slope means this line falls

22) (-2,5), (-2,4)

The slope is $m=\frac{4-5}{-2- -2}=\frac{-1}{0}$ = undefined

An undefined slope means this line is vertical

23) The given point is (0,8) (2,10)

The slope is $m=\frac{10-8}{2-0}=\frac{2}{2}=+1$

A positive slope means this line rises

24) The points are (-3,-3), (3,1)

The slope is $m=\frac{1--3}{3--3}=\frac{4}{6}=+\frac{2}{3}$

A positive slope means this line rises

25) The points are: (5,0) (6,-2)

Slope: $m=\frac{-2-0}{6-5}=\frac{-2}{1}=-2$

A negative slope means this line falls

26) The points are (-2,-8) , (5,-8).

Slope: $m=\frac{-8--8}{5--2}=\frac{0}{7}=0$

A zero slope means this line is horizontal

27) The points are: (-1,2) , (5,3)

Slope: $m=\frac{3-2}{5--1}=+\frac{1}{6}$

A positive slope means this line rises

28) The points are: $(\frac{1}{2},4)$ , (-1,4)

Slope: $m=\frac{4-4}{-1-\frac{1}{2}}=\frac{0}{\frac{1}{2}}=0$

A zero slope means the line is horizontal

29) The points are: $(4,\frac{1}{2}), (5,\frac{1}{4})$

Slope: $m=\frac{\frac{1}{4}-\frac{1}{2}}{5-4}=-\frac{1}{4}$

A negative slope means this line falls.

6 0

3 years ago

Let the smallest of 4 consecutive odd numbers be 2 n + 1 , where n is an integer. Show, using algebra, that the sum of any 4 con

andrey2020 [161]

Answer:

Expression is 8(n+2)

Step-by-step explanation:

smallest of 4 consecutive odd numbers =2n + 1

consecutive odd integers are found by adding 2 to the any given odd numbers

Thus, 2nd consecutive odd integers = 2n + 1 + 2 = 2n + 3

3rd consecutive odd integers = 2n + 3 + 2 = 2n + 5

2nd consecutive odd integers = 2n + 5 + 2 = 2n + 7

Thus, 4 consecutive odd integers are

2n + 1 ,2n + 3,2n + 5,2n + 7

sum of these numbers are = 2n + 1 +2n + 3 + 2n + 5+2n + 7 = 8n+16

sum of these numbers are = 8(n+2)

Thus, we see that the sum of numbers are 8(n+2)

As, 8 is common for n+2, whatever is value of n, the number will be multiple of 8 .

thus expression is 8(n+2)

7 0

3 years ago