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Andrej [43]
3 years ago
14

The unit cost, in dollars, to produce bins of cat food is $4 and the fixed cost is $18424. The revenue function, in dollars, is

R(x)=−2x^2+478x
Find the cost function.
C(x)=
Find the profit function.
P(x)=
At what quantity is the smallest break-even point?
Mathematics
1 answer:
Inessa [10]3 years ago
8 0

Answer:

49

Step-by-step explanation:

The cost function is the sum of the costs as a function of the number of bins made.

C(x) = 4x + 18424

The profit function is the difference between the revenue and the cost functions.

P(x) = R(x) - C(x)

P(x) = -2x^2 + 478x - (4x + 18424)

P(x) = -2x^2 + 474x - 18424

The smallest break-even point is the smallest value of x at which profit is zero. Zero profit means there is no gain and no loss.

P(x) = -2x^2 + 474x - 18424 = 0

x^2 - 237x + 9212 = 0

9212 = 2^2 * 7^2 * 47

(x - 188)(x - 49) = 0

x - 188 = 0 or x - 49 = 0

x = 188 or x = 49

Answer: 49

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Ainat [17]

Answer:

(i) The area of the rabbit cage when the width is 5.2 m is 81.5 m²

(ii) The area of the rabbit cage if Wilson has 40 meters of wire mesh is 75 m²

Step-by-step explanation:

(i) The given relation of the area, A to the width P of the rabbit cage is A = 3·p²

The graph of the function between the values of 0 and 6 inclusive is found as follows;

A,              3·p²

0,               0

1,                1

2,               12

3,               27

4,               48

5,               75

6,               108

Please find attached the graph of A to 3·p²

From the graph, we have when the the width, p, of the rabbit cage = 5.2, the area, A ≈ 81.5 m²

The area of the rabbit cage when the width is 5.2 m = 81.5 m²

(ii) Also from the graph given that the total wire mess with Wilson = 40 meters, we have;

The formula for the perimeter of the cage = The formula for the perimeter of a rectangle = 2×length + 2×width

The formula for the perimeter of the cage = 2×3×p + 2× p = 8·p

Where the total length of the wire mesh available = 40 meters for the cage

The 40 meters of wire mesh will be used round the perimeter of the cage

∴ 40 m. = 8·p

p = 40/8 = 5 m.

At p = 5 m. the area is given as A = 75 m².

Therefore, the area of the rabbit cage if Wilson has 40 meters of wire mesh = 75 m².

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3 years ago
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