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2 years ago

Can someone help me out? Will mark brainiest

Mathematics

1 answer:

enot [183]2 years ago

4 0

Ok done. Thank to me :>

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The total simple interest on $1600 invested for five years is $224. What is the percentage rate per annum?

mash [69]

Answer:

The percentage rate per annum is 2.8%

Step-by-step explanation:

We need to multiply the principal by the time, then divide the interest by the product of P×T, so:

1,600 × 5 = 8,000

224 ÷ 8,000 = 0.028

Then we convert our final product to a percentage.

0.028 to a percent is 2.8%

6 0

2 years ago

Read 2 more answers

HELP!!!!!!

Andreas93 [3]

Answer: (x2 – 1) – 5(x – 1)

7 0

2 years ago

Read 2 more answers

Using scientific notation, what is the solution to (2.82 * 104) * (3.1 * 103)?

MArishka [77]

Answer: Choice A) 8.742 * 10^7

=====================================

Work Shown:

$(a * 10^b) \times (c * 10^d) = a*c*10^{b+d}\\\\(2.82 * 10^4) \times (3.1 * 10^3) = 2.82*3.1*10^{4+3}\\\\(2.82 * 10^4) \times (3.1 * 10^3) = 8.742*10^{7}\\\\$

Extra info:

$8.742 * 10^7 = 87,420,000$

which is a little over 87.4 million

6 0

2 years ago

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

2 years ago

X-y=2<br>x² -7y² = 2<br>decide the system

olya-2409 [2.1K]

Wish I can help my g

7 0

2 years ago