Find the equation of a line perpendicular to -4x+y=10 that passes through the point (-4,9)
1 answer:
Answer:
y=-1/4x+8
Step-by-step explanation:
To find the equation of a line that is perpendicular to a line, you would take the opposite reciprocal of the slope.
Before that, we need to change the equation into slope-intercept form.
-4x+y=10
y=4x+10
The opposite reciprocal of the slope is -1/4.
Now, let's use the point-slope formula to find our equation of the line that passes through (-4,9).
y-y1=m(x-x1)
y-9=-1/4(x-(-4))
y-9=-1/4x-1
y=-1/4x+8
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X/-3 = 12 + x
x = -36 - 3x
4x = 36
x= = 9
The number is 9.
Answer:
40 daps
Step-by-step explanation:
lets say daps is d, yaps are y and baps are b
4d = 7y, 5y=3b
First convert to y
4/7d = y
Now convert that to b
5(4d/7) = 3b
20d / 7 = 3b
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Plug it in:
42(20d/21)
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aka 40 daps
Answer:
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
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Answer:
X=1/5
Step-by-step explanation:
7×-2×-10=-9
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5×/5=1/5
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