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stealth61 [152]
3 years ago
15

Find the equation of a line perpendicular to -4x+y=10 that passes through the point (-4,9)

Mathematics
1 answer:
Oliga [24]3 years ago
4 0

Answer:

y=-1/4x+8

Step-by-step explanation:

To find the equation of a line that is perpendicular to a line, you would take the opposite reciprocal of the slope.

Before that, we need to change the equation into slope-intercept form.

-4x+y=10

y=4x+10

The opposite reciprocal of the slope is -1/4.

Now, let's use the point-slope formula to find our equation of the line that passes through (-4,9).

y-y1=m(x-x1)

y-9=-1/4(x-(-4))

y-9=-1/4x-1

y=-1/4x+8

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Which equation has a y-intercept at (0,3) and a x-intercept at (-4,0)
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------------------------------------
Find slope first
Slope = \frac{y2-y1}{x2-x1}
0 - 3  = -3
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-4 - 0 = -4
--------------------------------------------------
Simplify -3/-4
3/4
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So your equation is y = 3/4x + 3


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3 years ago
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