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3 years ago

Elsa tries to solve the following equation, and determines there is no solution. Is she correct? Explain.

Mathematics

2 answers:

GaryK [48]3 years ago

7 0

The spot on correct answer for this is....

Identify the system of equations that can be graphed to solve the problem.

Use the change of base formula.

Determine that the graphs of the two equations do not intersect.

Determine that Elsa is correct; the equation has no solution.

Vlad [161]3 years ago

3 0

Elsa's answer is incorrect since there is a solution of the given equation. In the given logarithmic problem, we need to simplify the problem by transposing log2(3x+5) in the opposite side. The equation will now be log2x-log2(3x+5)=4. Using properties of logarithm, we further simplify the problem into a new form log (2x/6x+10)=4. Then transform the equation into base form 10^4=(2x/6x+10) and proceed in solving for x value which is equal to 1.667.

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I need help with this in 7th grade just started to learn this

tatuchka [14]

Answer:

Step-by-step explanation:

110% × 90 = 99

OR

110/100 × 90 (Simplify this)

11/10 × 90 (Divide 10 into 90 / Cross multiply)

11 × 9 = 99

8 0

3 years ago

What is the domain of the function f(x) = 5x+2? XS-6 0 x>6 0x<6 O x>-6

Sholpan [36]

I think your equation is wrong. the domain of f(x)= 5x+2 is ALL REAL NUMBERS. That means it’s negative infinity to positive infinity.

3 0

2 years ago

Here’s another way to think about the number line model for 2 – (-3): if we were adding 2 + (-3), we’d first move two units to t

CaHeK987 [17]

Subtracting -9 from any number is the same as

A

subtracting 9 from that number.

7 0

3 years ago

Given f(x)=e^-x^3 find the vertical and horizontal asymptotes

Aleonysh [2.5K]

Given:

$f\mleft(x\mright)=e^{-x^3}$

To find the vertical and horizontal asymptotes:

The line x=L is a vertical asymptote of the function f(x) if the limit of the function at this point is infinite.

But, here there is no such point.

Thus, the function f(x) doesn't have a vertical asymptote.

The line y=L is a vertical asymptote of the function f(x) if the limit of the function (either left or right side) at this point is finite.

$\begin{gathered} y=\lim _{x\rightarrow\infty}e^{-x^3} \\ =e^{-\infty} \\ y=0 \\ y=\lim _{x\rightarrow-\infty}e^{-x^3} \\ y=e^{\infty} \\ =\infty \end{gathered}$

Thus, y = 0 is the horizontal asymptote for the given function.

5 0

9 months ago

Please help !!! I’m stuck

Kruka [31]

Answer:

2/3 ≈ 0.6667

Step-by-step explanation:

apply soh cah toa

sine=opposite/hypo

sine=4/6

sine=2/3

4 0

2 years ago