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sineoko [7]
3 years ago
11

An item is priced at $80. It is on sale for 20% off the regular price. What is the sale price?

Mathematics
1 answer:
Masja [62]3 years ago
4 0
Regular Pirce = $80.

Discount = 20%

Discount = 20% x $80 = 0.2 x 80 = $16

Sale Price = 80 - 16 = $64

----------------------------------------------------
Answer: The Sale Price is $64.
----------------------------------------------------
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the volume of the pyramid = 5cm³

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Step-by-step explanation:

the volume of the pyramid = (b×h)/3 = (2²×3,75)/3 = (4×3,75)/3 = 15/3 = 5.

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True or False? <br><br> Set A = { X | X is an even whole number between 0 and 2} = ∅
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It is false because 0and 2 and the middle number will be 1

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How many 3 3/4 inch wires can be cut from a spool if wire that is 100 inches how much will be left over
Akimi4 [234]

How many 3\frac{3}{4} wires can be cut from a spool of wire that is 100 inches long?

How many inches will be left over?

Number of pieces of wires = length of spool of wire ÷ length of each piece of wire.

Number of pieces = 100 ÷ 3\frac{3}{4} = 100 ÷ \frac{15}{4}

That gives \frac{100 * 4}{15}

Simplifying gives \frac{400}{15} = \frac{80}{3}

This is equivalent to 26\frac{2}{3} pieces

So 26 pieces of wires can be cut from a spool and \frac{2}{3} of a piece will be left over.

6 0
3 years ago
For the given hypothesis test, determine the probability of a Type II error or the power, as specified. A hypothesis test is to
erica [24]

Answer:

the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

Step-by-step explanation:

Given the data in the question;

we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.

as in it in the question;

obtained mean is 9.8 which is obviously not equal to 8.3

But still we fail to reject the null hypothesis says mean is 8.3

Hence we have to find the probability of type 11 error

given that; it is right tailed and o.5, it corresponds to 1.645

so

z is equal to 1.645

z = (x-μ)/\frac{S}{\sqrt{n} }

where our standard deviation s = 3.8

sample size n = 50

mean μ = 8.3

we substitute

1.645 = (x - 8.3)/\frac{3.8}{\sqrt{50} }

1.645 = (x - 8.3) / 0.5374

0.884023 = x - 8.3

x = 0.884023 + 8.3

x = 9.18402

so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645

As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value

so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402

Now, for mean 9.8 and standard deviation 3.8 and sample size 50

Z =  (9.18402 - 9.8)/\frac{3.8}{\sqrt{50} }

Z = -0.61598 / 0.5374

Z = - 1.1462 ≈ - 1.15

from the z-score table;

P(z<-1.15) = 0.1251

Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

8 0
2 years ago
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