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andrey2020 [161]
2 years ago
6

A construction crew is paving a road. The crew has already paved 1,000 square feet and can pave at a rate of 300 square feet of

road per hour. The function f(x) = 300x + 1,000 represents this situation.
What is f(3), and what does it represent?


900 square feet; f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount.
900 square feet;, f, (3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount.

900 square feet; f(3) represents the total number of square feet the construction crew has paved after 3 hours.
900 square feet; , f, (3) represents the total number of square feet the construction crew has paved after 3 hours.

1,900 square feet; f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount.
1,900 square feet;, f, (3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount.

1,900 square feet; f(3) represents the total number of square feet the construction crew has paved after 3 hours.
Mathematics
1 answer:
denis23 [38]2 years ago
6 0

Answer:

1,900 square feet; f(3) represents the total number of square feet the construction crew has paved after 3 hours.

The function of the construction crew is an illustration of a linear function

The value of f(3) is 1900, and f(3) represents the total number of square feet paved after working for 3 hours

The function is given as:

To calculate f(3), we substitute 3 for x

Multiply 300 and 3

Add 900 and 1000

This means that the value of f(3) is 1900.

And it represents the total number of square feet paved after working for 3 hours

1,900 square feet; f(3) represents the total number of square feet the construction crew has paved after 3 hours.

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Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
2 years ago
A physical fitness association is including the mile run in its secondary-school fitness test. The time for this event for boys
Luba_88 [7]

Answer:

z=-1.28

And if we solve for a we got

a=470 -1.28*60=393.2

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would earn a certificate of recognition from the fitness association

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the time for this event of a population, and for this case we know the distribution for X is given by:

X \sim N(470,60)  

Where \mu=470 and \sigma=60

NOTE: For this case the fastest 10% is on the lower tail of the distribution

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.9   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.1 of the area on the left and 0.9 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.1 and P(z>-1.28)=0.9

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-1.28

And if we solve for a we got

a=470 -1.28*60=393.2

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would  earn a certificate of recognition from the fitness association

4 0
3 years ago
1 Which relation is not a function?
Karo-lina-s [1.5K]
3 because the x value has been repeated
6 0
3 years ago
Read 2 more answers
Willy Wonka has 2 candies, Wonka bars and Everlasting Gobstoppers. Both have both natural sugar and sucrose in them. Each Wonka
love history [14]

Answer:

Wonka bars=3 and  Everlasting Gobstoppers=24

Step-by-step explanation:

let the wonka bars be X

and everlasting gobstoppers be Y

the objective is to

maximize 1.3x+3.2y=P

subject to constraints

natural sugar

4x+2y=60------1

sucrose

x+3y=75---------2

x>0, y>0

solving 1 and 2 simultaneously we have

4x+2y=60----1

x+3y=75------2

multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have

 4x+2y=60

 4x+12y=300

-0-10y=-240

10y=240

y=240/10

y=24

put y=24 in equation 2 we have'

x+3y=75

x+3(24)=75

x+72=75

x=75-72

x=3

put x=3 and y=24 in the objective function we have

maximize 1.3x+3.2y=P

1.3(3)+3.2(24)=P

3.9+76.8=P

80.7=P

P=$80.9

8 0
3 years ago
Please help ASAP
salantis [7]

Answer:

0.5 m/s

Falling at 32 feet/s

Step-by-step explanation:

For the first question, since it only asks for the average time between 2 and 8 seconds, those are the only two important values. When taking the inputs and outputs for 2 and 8 seconds after the throw ((2,3) and (8,6) respectively), we can take the average change by finding the change in y/change in x, so we have (6-3)/(8-2)=0.5 meters/second.

For the second question, we can similarly just take the values from the initial drop (144) and after two seconds (80) to get that the rate of change is (144-80)/(-2)=-32, so it's falling at 32 feet/second.

Let me know if you have any questions!

8 0
3 years ago
Read 2 more answers
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