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sukhopar [10]
3 years ago
8

Two of the exterior angles of a triangle are $158^\circ$ and $99^\circ.$ Find the third exterior angle, in degrees.

Mathematics
1 answer:
Lisa [10]3 years ago
4 0

Answer:

The third exterior angle is 103^o

Step-by-step explanation:

Given

\theta = 158^o

\alpha = 99^o

Required

The third exterior angle (\beta)

The exterior angles of a triangle add up to 360 degrees.

So:

\theta + \alpha + \beta = 360^o

Make \beta the subject

\beta = 360^o - (\theta + \alpha)

Substitute known values

\beta = 360^o - (158^o + 99^o)

\beta = 103^o

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