1.
a) metres to centimetres :
multiply length by 100
b) metres to millimetres:
multiply length by 1000
c) kilograms to grams:
multiply the mass value by 1000
d) litres to millilitres :
multiply volume by 1000
2.
a) 3 m = 3× 100 = 300 cm
b) 28 cm = 28 × 10 = 280 mm
c) 2.4 km = 2.4 × 1000
= 24 × 10^-1 × 10^3
= 24 × 10^2 =2400 m
d) 485 mm =485 / 10
= 485 / 10 ^1
= 485 × 10 ^-1
= 48.5 cm
e) 35 cm = 35 / 100
= 35 /10^2
= 35 × 10 ^ -2
= 0.35 m
f) 2.4 m = 2.4 / 1000
= 24 × 10 ^-1 / 10^3
= 24 × 10^-1 × 10 ^-3
= 24 × 10 ^ -4
= 0.0024 km
g) 2495 mm = 2495 /1000
= 2495 /10^ 3
= 2495 × 10 ^-3
=2.495 m
Answer:
"impossible"
Step-by-step explanation:
I think. :/
Well, we need to consider the x and y coordinates of the giben points, and check wether the y coordinate is greater than twice the x coordinate minus 1 (i.e. 2x-1):
- For the first point, the x coordinate is 0. So, 2x-1 = -1. The y coordinate is 2, and 2>-1. So, this point is a solution.
- For the second point, the x coordinate is 4. So, 2x-1 = 7. The y coordinate is 2, and 2<7. So, this point is not a solution.
- For the third point, the x coordinate is 0. So, 2x-1 = -1. The y coordinate is -10, and -10<-1. So, this point is not a solution.
- For the fourth point, the x coordinate is 4. So, 2x-1 = 7. The y coordinate is 1, and 1<7. So, this point is not a solution.
It’s B
If y-x=6
Y +X =_10
then y= 6 + x, instead of y insert this no
6+ x+ x =-10
6 + 2x =-10 then collect like terms
2x =-10-6
2x=-16 then multiple both side by 1/2
X=-8
Y=6+x instead of x insert -8
Y=6-8
=-2
