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Ksju [112]
2 years ago
14

Can y’all please help me answer these questions

Mathematics
2 answers:
mario62 [17]2 years ago
6 0

Step-by-step explanation:

4.

⇒ V = \pi r^{2}h

⇒ V = \pi(10)^{2}(40)

⇒ V = 4000\pi

⇒ V = 12566.4cm^{3}

5.

⇒ V = \frac{1}{3}\pi r^{2}h

⇒ V = \frac{1}{3}\pi (8)^{2}(h)

As we know the radius and slant height, we can use Pythagoras' Theorem to find the perpendicular height.

⇒ a^{2} + b^{2} = c^{2}

⇒ (8)^{2} + h^{2} = 20^{2}

⇒ h = \sqrt{20^{2} - 8^{2}}

⇒ h = 4\sqrt{21}

Now substitute this into the volume formula.

⇒ V = \frac{1}{3}\pi (8)^{2}(4\sqrt{21})

⇒ V = \frac{256\sqrt{21} }{3}\pi

⇒ V = 1228.5mm^{3}

6.

⇒ V = l^{3}

⇒ V = (3.1)^{3}

⇒ V = 29.8inches^{3}

7.

⇒ V = \frac{1}{3}lwh

⇒ V = \frac{1}{3}(12)(4)(6)

⇒ V = 96inches^{3}

nignag [31]2 years ago
4 0

Answer : 4. 12571.429.

5. 4022.857

6. 29.791

7. 96

Step-by-step explanation:

4. FORMULA: PIE R SQUARE TIMES HEIGHT

5. FORMULA: the same as the previous formula

6. FORMULA: LENTH × WIDTH × HEIGHT

7. FORMULA: 1/3 × L × W × H

4. 22/7×10×10×40 = 12571.429

5. 22/7×8×8×20 = 4022.857

6. 3.1 × 3.1 × 3.1 = 29.791

7. 1/3 × 12 × 4 × 6 = 96

HOPE THIS HELPS U

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Step-by-step explanation:

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The answer to your question is There is only one solution (0, -2)

Step-by-step explanation:

Data

Equation 1     x - y = 2

Equation 2    x + y = -2

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                          y = x - 2

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Step-by-step explanation:

Part C: (Explanation with steps)

Let the length of the swimming pool = l feet

And width of the pool = w feet

Perimeter of the pool = 2(l + w) feet

Since, perimeter of the pool = 8 feet

2(l + w) = 80

l + w = 40

l = (80 - w) -------(1)

Area of the pool = Length × width

A(w) = l × w

By substituting the value of l from equation (1)

A(w) = (80 - w) × w

A(w) = 80w - w²

To find the maximum area of the pool we will find the derivative of the function with respect to 'w' and equate it to zero.

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(80 - 2w) = 0

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Therefore, for width (w) = 40 feet area of the pool will be maximum.

From equation (1),

l = 80 - 40

l = 40 feet

Therefore, maximum area of the pool = l × w

                                                               = 40 × 40

                                                               = 1600 square feet

Part A:

Function representing area of the pool,

A(w) = -w² + 80w

Part B:

Maximum area of the surface of the pool = 1600 square feet

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