Question

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Answer 1

Answer:

$\lim_{x\to 0^+} \tan(x) - \frac{1}{x^2} = -\infty$

Step-by-step explanation:

$\lim_{x\to 0^+} \tan(x) - \frac{1}{x^2} = \lim_{x\to 0^+} \tan(x) - \lim_{x\to 0^+} \frac{1}{x^2}$

and

$\lim_{x\to 0^+} \tan(x) = \tan(0) = 0$

$\lim_{x\to 0^+} \frac{1}{x^2} = +\infty$

Therefore,

$\lim_{x\to 0^+} \tan(x) - \frac{1}{x^2} = -\infty$

Answer 2

Answer:

000

Step-by-step explanation:

000