Question

Please help.with the steps​

Answer 1

Answer:

  -4/243

Step-by-step explanation:

Your calculator can do this.

You know that 3³ = 27 and (-3)³ = -27. You also know that 3² = 9, and that anything to the zero power is 1. With these facts, you can simplify the expression to ...

  $\dfrac{\sqrt[3]{-27}-27^0}{3^3\times3^2}=\dfrac{-3-1}{27\times9}=\boxed{-\dfrac{4}{243}}$