Answer:
Step-by-step explanation:
When you have four terms and 3rd degree equation (the highest power is 3) you will want to try to "factor by grouping"
Group together two terms, watch out for the negative signs!
x^3 + 2x^2-5x-10=0
(x^3 + 2x^2) - (5x+10)=0
Find a common factor in each group and factor it out. You're hoping that what is left in the parenthesis is the same in both cases.
x^2(x+2)-5(x+2)=0
Now you can factor out that (x+2) because it is both terms.
x^2(x + 2) - 5(x + 2)=0
~~~~ ~~~~
Pull these out.
What will be left is the x^2 and the - 5 (dont lose that - in front of the 5)
(x + 2)(x^2 - 5) = 0
If all you have to do is factor, then you're done. It is factored. But if you have to "solve" also, then put x+2=0 and x^2-5=0 and solve.
x = -2 and x = +- sqrt5
