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2 years ago

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$\sqrt{3 + 3 + 3 + 3 + 3 + 3}$

Mathematics

1 answer:

timofeeve [1]2 years ago

3 0

Answer:

3√2

Step-by-step explanation:

First, combine all the numbers in the square root, and then square root the number provided:

√(3 + 3 + 3 + 3 + 3 + 3) = √18

When square rooting, first, find prime factors of the number, 18. If there are pairs, they will be combined into a whole number:

√18 = √(3 * 3 * 2) = 3√2

3√2 is your answer.

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Which is greater 1/3 or 7/12

Paladinen [302]

Answer:

7/12

Step-by-step explanation:

1/3 or seven 7/12?

First find the common denominator, in this case 12

1/3 x 4 = 4/12

4/12 or 7/12?

7/12 is greater!

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3 years ago

Rewrite the equation 7-y=5x+11 to standard form

Zielflug [23.3K]

Rewriting this <span>7-y=5x+11 in standard form involves only changing the order in which the terms appear:

</span><span>7-y=5x+11 becomes 5x + y + 11 - 7 = 0, or 5x + y + 4 = 0, or 5x + y = -4.</span>

4 0

3 years ago

Simplify \root(3)(8x^(6))y^(12)

ExtremeBDS [4]

The simplification form of the provided expression is 2x²y⁴ option first is correct.

<h3>What is an expression?</h3>

It is defined as the combination of constants and variables with mathematical operators.

We have an expression:

$= \rm \sqrt[3]{8x^6y^{12}}$

$\rm =\sqrt[3]{8}\sqrt[3]{x^6}\sqrt[3]{y^{12}}$

$\rm \rm = \rm 2\sqrt[3]{x^6}\sqrt[3]{y^{12}}$

$\rm =2x^2\sqrt[3]{y^{12}}$

$\rm =2x^2y^4$

Thus, the simplification form of the provided expression is 2x²y⁴ option first is correct.

Learn more about the expression here:

brainly.com/question/14083225

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4 0

3 years ago

a person goes from a sauna at 115°F to an out side temperature of -30°F. what is the change in temperature?

Oksana_A [137]

Whenever you're interested in computing the (absolute) difference between two values of a certain variable, you have to subtract the final value and the initial value. This is often written as delta:

$\Delta x = x_{\text{final}} - x_{\text{initial}}$

So, in this case, the final temperature is -30°F. The initial temperature is 115°F. So, the variation is

$\Delta T = T_{\text{final}} - T_{\text{initial}} = -30 - 115 = -145$

A negative delta indicates that the value decreased, which is our case.

7 0

4 years ago

Suppose that the number of asbestos particles in a sample of 1 squared centimeter of dust is a Poisson random variable with a me

Maslowich

Answer:

The approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357

Step-by-step explanation:

For a sample of 10 sqaured centimeters of dust, the total amount of asbestos particles has a Poisson distribution with a mean of 1000/1 * 10 = 10000.

We will approximate this probability to a normal distribution. The variance is also 10000 (because it is poisson), therefore the standard deviation is √10000 = 100. Lets call X the distribution, and W its standarization, given by

$W = \frac{X-\mu}{\sigma} = \frac{X-10000}{100}$

We have

$P(X>10110) = P(\frac{X-10000}{100} > \frac{10110-10000}{100}) = P(W > 1,1) = 1-\phi(1,1) = 1-0.8643 = 0.1357$

Where $\phi$ is the cummulative distribution function of a standard normal distribution. The values of $\phi$ are well known and they can be found in the attached file.

We conclude that the approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357.

Download pdf

4 0

3 years ago