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4 years ago

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Latrell has $8 to spend on postcards. He wants to buy one large postcard and some small ones. Write and solve an inequality to d

etermine how many small postcards Latrell can purchase. Interpret the solution.

1 answer:

fgiga [73]4 years ago

8 0

I have had this worksheet

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Find P(A or B) if the events are disjointed. P(A) =6/25 , and P(B) =9/25 .

nevsk [136]

Here, "disjointed" signifiies that Event A and Event B are independent; neither outcome influences the other. In such a case, the union of A and B is given by the sum of the two probabilities P(A) and P(B).

Here, that sum is P(A or B) = 6/25 + 9/25, or 15/25, or 0.6.

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3 years ago

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Solve for n.<br> (33)^2 = n^6

lapo4ka [179]

Answer is

n=3.207534,−3.207534

Step-by-step explanation: looked it up lol.

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3 years ago

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Directions: Describe each pair of ratio. Tell whether it is a proportion

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3 years ago

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The Grand Canyon is approximately 2^9 kilometers long. Mariner Valley is a canyon on Mars that is approximately 2^12 kilometers

omeli [17]

Is about 1000 bigger 2^12/2^9 = 1000

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3 years ago

Find a solution to the following initial-value problem: dy dx = y(y − 2)e x , y (0) = 1.

Veseljchak [2.6K]

This equation is separable, as

$\dfrac{\mathrm dy}{\mathrm dx}=y(y-2)e^x\implies\dfrac{\mathrm dy}{y(y-2)}=e^x\,\mathrm dx$

Integrate both sides; on the left, expand the fraction as

$\dfrac1{y(y-2)}=\dfrac12\left(\dfrac1{y-2}-\dfrac1y\right)$

Then

$\displaystyle\int\frac{\mathrm dy}{y(y-2)}=\int e^x\,\mathrm dx\implies\frac12(\ln|y-2|-\ln|y|)=e^x+C$

$\implies\dfrac12\ln\left|\dfrac{y-2}y\right|=e^x+C$

Since $y(0)=1$ , we get

$\dfrac12\ln\left|\dfrac{1-2}1\right|=e^0+C\implies C=-1$

so that the particular solution is

$\dfrac12\ln\left|\dfrac{y-2}y\right|=e^x-1\implies\boxed{y=\dfrac2{1-e^{2e^x-2}}}$

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3 years ago