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3 years ago

6

A gardener has 27 pansies and 36 daisies he plans on equal number of each type of flower and a trend what is the greatest possib

le number of pansies in each row

1 answer:

vaieri [72.5K]3 years ago

7 0

9 because it's the gcf(greatest common factor)

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I need to know if these answers are correct or not...

AlladinOne [14]

1. Let the four consecutive numbers be x, x+1, x+2, x+3

The sum of four consecutive number is already given to us = 70

Therefore

⇒(x)+(x+1)+(x+2)+(x+3)=70

We need to combine x as we have four x terms in the equation. The next step is to get all of the x’s on one side of the equation and all the numbers on the other side. The same rule applies – whatever you do to one side of the equation, you must do to the other side as well!

⇒4x+6=70⇒4x=64⇒x=16

So, the four numbers are 16, 17, 18 and 19.

Hence, the greatest number among them is 19.

4 0

2 years ago

Lorenzo tiene 4 cajas de huevo, cada uno con 50 huevos y 3 cartones del mismo producto con 10 de ellos ¿Cuántos huevos hay en to

Bogdan [553]

Responder:

240 huevos

Explicación paso a paso:

Número de cajas de huevos = 4

Huevos por caja = 50

Total de huevos en caja = 50 * 4 = 200 huevos

Número de cajas = 3

Número de huevos por caja = 10

Total de huevos en caja = 10 * 4 = 40 huevos

Huevos totales = (huevos en caja + huevos en cartón)

Total = (200 + 40) = 240 huevos

3 0

3 years ago

What is the square root of 48 simplified?

ivanzaharov [21]

The square root of 48 simplified is 4 sqrt 3.

6 0

2 years ago

Read 2 more answers

Whai si (3x+5) (x-2)

Vika [28.1K]

The answer is 3x squared -11x-10

3 0

2 years ago

Need help with AP CAL

anzhelika [568]

Answer: Choice C

$\displaystyle \frac{1}{2}\left(1 - \frac{1}{e^2}\right)$

============================================================

Explanation:

The graph is shown below. The base of the 3D solid is the blue region. It spans from x = 0 to x = 1. It's also above the x axis, and below the curve $y = e^{-x}$

Think of the blue region as the floor of this weirdly shaped 3D room.

We're told that the cross sections are perpendicular to the x axis and each cross section is a square. The side length of each square is $e^{-x}$ where 0 < x < 1

Let's compute the area of each general cross section.

$\text{area} = (\text{side})^2\\\\\text{area} = (e^{-x})^2\\\\\text{area} = e^{-2x}\\\\$

We'll be integrating infinitely many of these infinitely thin square slabs to find the volume of the 3D shape. Think of it like stacking concrete blocks together, except the blocks are side by side (instead of on top of each other). Or you can think of it like a row of square books of varying sizes. The books are very very thin.

This is what we want to compute

$\displaystyle \int_{0}^{1}e^{-2x}dx\\\\$

Apply a u-substitution

u = -2x

du/dx = -2

du = -2dx

dx = du/(-2)

dx = -0.5du

Also, don't forget to change the limits of integration

If x = 0, then u = -2x = -2(0) = 0
If x = 1, then u = -2x = -2(1) = -2

This means,

$\displaystyle \int_{0}^{1}e^{-2x}dx = \int_{0}^{-2}e^{u}(-0.5du) = 0.5\int_{-2}^{0}e^{u}du\\\\\\$

I used the rule that $\displaystyle \int_{a}^{b}f(x)dx = -\int_{b}^{a}f(x)dx$ which says swapping the limits of integration will have us swap the sign out front.

--------

Furthermore,

$\displaystyle 0.5\int_{-2}^{0}e^{u}du = \frac{1}{2}\left[e^u+C\right]_{-2}^{0}\\\\\\= \frac{1}{2}\left[(e^0+C)-(e^{-2}+C)\right]\\\\\\= \frac{1}{2}\left[1 - \frac{1}{e^2}\right]$

In short,

$\displaystyle \int_{0}^{1}e^{-2x}dx = \frac{1}{2}\left[1 - \frac{1}{e^2}\right]$

This points us to choice C as the final answer.

5 0

2 years ago