Answer:
The measure of angle DPA is 39°
Step-by-step explanation:
step 1
Find the value of x we know that arc AB+arc BC+arc CD+arc DA=360°
substitute the values
(5x+10)°+(x+1)°+3x°+(3x+25)°=360°
Solve for x
(12x+36)°=360°
12x=360°-36°
x=324°/12=27°
step 2 Find the measure of angle DPA
we know that The measurement of the external angle is the semi-difference of the arcs which comprises
m∠DPA=(1/2)[arc DA-arc BC]
arc DA=3(27)+25=106°
arc BC=27+1=28°
substitute the values
m∠DPA=(1/2)[106°-28°]=39°
C. -X to the 3rd power, 4x to the second power and 5x all share the common factor or X, therefore you put it outside the parenthesis. What you have left is -X to the second power minus 4x minus 5.
Answer:
C
Step-by-step explanation:
The 6 comes from the 24(6*4=24)
The 3 comes from the 12(3*4=12)
The 4 is common
Answer:
C
Step-by-step explanation:
Given
2x² + x - 1 = 2 ( subtract 2 from both sides )
2x² + x - 3 = 0
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × - 3 = - 6 and sum = + 1
The factors are - 2 and + 3
Use these factors to split the x- term
2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )
2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(2x + 3) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - 
D) The median of 2nd Period is greater than the median of 1st Period.
The one that's true
Hope this helps!
