The digit 6 is in the Hundred Thousand Place.
The value of the angles should be. (x-40°). , (x-20°), (½x-10°) , not (x-40°) + (x-20°)+(½x-10°)
Sum of all the interior angles of a triangle is 180°.
So a equation can be made by the given data,
(x-40°) + (x-20°) + (½ x-10°) = 180°
x-40°+x-20°+½x-10° = 180°
2x+½x -60°-10° = 180°
5/2 x - 70° = 180°
5/2 x = 180° + 70°
5/2 x = 250°
x = 250° × 2/5
x = 50° × 2
x = 100°
So the angles are
x-40° = 100°-40° = 60°
x-20° = 100°–20° = 80°
½x-10° = ½(100)° - 10° = 50° -10° = 40°
The answer can be checked by putting the values of the angle we got in the second statement i.e. Sum of all the interior angles of a triangle is 180°.
60° + 80° + 40° = 100° + 80° = 180°
3a^2 B^3 C^-2 OVER a^-3 b^6 c^3
3.) 2 × 0.5 = 1
4.) -2 × -0.5 = 1
