Question

Write an equation of a line that is parallel to y=-6x+4 and passes through(2,10).

Answer 1

A)y=-6x+4
Slope and intercept a=-6 b=4
equation for new line:
y=cx+d
If new line is parallel c=a=-6 so
y=-6x+d
We substitude point (2,10)
10=-6*2+d /+12
d=22
so y=-6x+22
b) 
y=-$\frac{2}{3}$x-5
a=-2/3
b=-5
new line:
y=ex+f
If line is perpendicular e=-$\frac{1}{a}$
so e=$\frac{3}{2}$
we can write 
y=$\frac{3}{2}x+f$
Substituting point (6,3)
3=$\frac{3}{2}*6+f$
f=3-9
f=-6
y=$\frac{3}{2}x-6$