Write an equation of a line that is parallel to y=-6x+4 and passes through(2,10).

1 answer:

3 0

A)y=-6x+4
Slope and intercept a=-6 b=4
equation for new line:
y=cx+d
If new line is parallel c=a=-6 so
y=-6x+d
We substitude point (2,10)
10=-6*2+d /+12
d=22
so y=-6x+22
b)
y=- $\frac{2}{3}$ x-5
a=-2/3
b=-5
new line:
y=ex+f
If line is perpendicular e=- $\frac{1}{a}$
so e= $\frac{3}{2}$
we can write
y= $\frac{3}{2}x+f$
Substituting point (6,3)
3= $\frac{3}{2}*6+f$
f=3-9
f=-6
y= $\frac{3}{2}x-6$

You might be interested in

729 = blank to the third power

Crazy boy [7]

One way is to factor and group and get every 3
729=3 times 3 times 3 times 3 times 3 times 3
so we group the ones that happen 3 times
729=(3*3*3) times (3*3*3)
we know that we can take the cube root of each group and multiply the result
729= $( \sqrt[3]{3*3*3})( \sqrt[3]{3*3*3})$ =(3)(3)=9

the answer is 9

4 0

3 years ago

How many four-digit whole numbers are there such that the leftmost digit is odd, the second digit is even, and all four digits a

kiruha [24]

Answer: There are 1400 different combinations.

Step-by-step explanation:

The conditions are:

we have 4-digits: abcd.

all the digits are different.

a is an odd number, and b is an even number.

Then, for a, we have the options 1, 3, 5, 7 and 9 (so we have 5 options).

for b, we have the options 0, 2, 4, 6 and 8 (so we have 5 options).

for c, we can have odd or even numbers, so we have 8 options ( remember that there where 2 numbers already taken away, this is why we have only 8 options).

for d we have 7 options (because 3 numbers are already taken).

Then the number of combinations is equal to the product of the number of options for each selection:

C = 5*5*8*7 = 1400

3 0

3 years ago

Complete the algebra terms with table and graph given y = 2x +3

Bezzdna [24]

It’s really easy all you have to do is plug in the numbers
(In order)
-1, 1, 3, 5, 7, 9

4 0

2 years ago

2/3+1/6???????????????????

kupik [55]