Answer:
2080 IU
Explanation:
Given
Ratio of vitamin A in cow milk to goat milk = 3 : 4
Required
Determine the content of vitamin A in goat milk if cow milk has 1560 IU
The given parameters shows a direct proportion.
Let G represents Goat and C represent Cow
Given that there exists a direct proportion;
C = K * G where K represents the constant of proportionality.
Solving for K when C = 3 and G = 4
C = K * G becomes
3 = K * 4
3 = 4K
Divide through by 4
¾ = K
K = ¾
Now, solving for G given that C = 1560IU;
We'll make use of the same formula as above
C = K * G
Substitute 1560 for C and ¾ for K; the expression becomes
1560 = ¾ * G
Multiply both sides by 4
4 * 1560 = 4 * ¾ * G
6240 = 3 * G
Multiply both sides by ⅓
⅓ * 6240 = ⅓ * 3 * G
2080 = G
G = 2080
Hence, the vitamin A in the goat milk is 2080IU
The target heart rate of the 45 year old client with a resting heart rate of 75 bpm is; 135 bpm
Complete question is;
A client is 45 years old and has a resting heart rate of 75 bpm using the karvonen formula what is their target heart rate at an exercise intensity of 60%.
We are given;
Age of client = 45 years
Resting Heart rate = 75 bpm
%Intensity = 60%
The karvonen formula is;
Target Heart Rate = [(max HR − resting HR) × %Intensity] + resting HR
Formula for maximum heart rate is;
Max HR = 220 - age
Max heart rate = 220 - 45
Max HR = 175 bpm
Thus;
Target Heart rate = [(175 - 75) × 0.6] + 75
Target Heart rate = (100 × 0.6) + 75
Target Heart rate = 60 + 75
Target Heart rate = 135 bpm
Read more on target heart rate at; brainly.com/question/7593179
According to Hooke's law, a 30-N force stretches a spring by 0.73 m if the spring constant k is such that
30 N = k (0.73 m)
k = (30 N) / (0.73 m)
k ≈ 4.1 N/m
