Answer:
662 nm
Explanation:
given,
camera lens of n = 1.5
magnesium fluoride n = 1.38
thickness = 120 n m = 120 × 10⁻⁹m
thickness =
wave length = 120× 10⁻⁹ × 4 × 1.38
= 0.662 × 10⁻⁶ m
= 662 nm
hence, the wavelength is equal to 662 nm
Answer:
Maximum height reached by the bullet = 4.01 m
Explanation:
Horizontal displacement = 92 m
Time taken = 6.4 s
Horizontal velocity
We have angle of projection = 32°
Horizontal velocity = u cos 32 = 14.375
u = 16.95 m/s
Vertical velocity = u sin θ = 16.95 x sin 32 = 8.98 m/s
Time of flight till it reaches maximum height = 0.5 x 6.4 = 3.2s
Now we have vertical motion of bullet
S = ut + 0.5 at²
Vertical velocity = u = 16.95 m/s
a = -9.81 m/s²
t = 3.2s
Substituting
S = 16.95 x 3.2 - 0.5 x 9.81 x 3.2² = 4.01 m
Maximum height reached by the bullet = 4.01 m
Answer:
Its diameter increases as it flows down from the pipe. Assuming laminar flow for the water, then Bernoulli's equation can be applied.
P1-P2 + (rho)g(h1 - h2) + 1/2(rho)(v1² - v2²) = 0
Explanation:
P1 = P2 = atmospheric pressure so, P1 - P2 = 0
h1 is greater than h2 so h1-h2 is positive. Rearranging the equation above 2{ (rho)g(h1-h2) + 1/2(rho)v1²}/rho = v2²
From the continuity equation for fluids
A1v1 = A2v2
v2 = A1v1/A2
Substituting into the equation above
(A1v1/A2)² = 2{ (rho)g(h1-h2) + 1/2(rho)v1²}/rho
Making A2² the subject of the formula,
A2² = (A1v1)²× rho/(2{ (rho)g(h1-h2) + 1/2(rho)v1²}
The denominator will be greater than the numerator and as a result the diameter of the flowing stream decreases.
Thank you for reading.