Answer:
D. Meters/Seconds
Explanation:
The time period of a wave is measured in seconds.
A typical wave involves both time and distance. Consider a sound wave, which is basically a periodic modulation of the local air pressure. We "hear" the sound because our ears respond to the variations of pressure.
The most common metric of a sound wave is frequency. This is the rate at which the change in pressure occurs, and is measured in cycles per second, formally known as "hertz". The period is the inverse of frequency andl has the units of seconds per cycle, commonly stated simply as seconds.
Answer:
Mass does not affect the pendulum's swing. The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.
Explanation:
Answer: T = 305.22 K
Explanation: given that
from -90 degree Fahrenheit to -5
degree Kelvins
Using the formula
(9/5 C) + 32 = F
Let's first convert degree Fahrenheit to degree Celsius
90 = 9C/5 + 32
9C/5 = 90 - 32
9C/5 = 58
9C = 290
C = 290/9
C = 32.22 degree Celsius
Convert degree Celsius to Kelvins
T = 273 + C
T = 273 + 32.22
T = 305.22K
Answer:
![g'=10.78\ m/s^2](https://tex.z-dn.net/?f=g%27%3D10.78%5C%20m%2Fs%5E2)
Explanation:
The time period of a simple pendulum is given by :
![T=2\pi \sqrt{\dfrac{L}{g}}](https://tex.z-dn.net/?f=T%3D2%5Cpi%20%5Csqrt%7B%5Cdfrac%7BL%7D%7Bg%7D%7D)
L is length of the pendulum and g is acceleration due to gravity
At the bottom of Death valley, g = 9.8 m/s²
We need to find the value of g if the period of the pendulum is decreased by 5.00%.
T'=(T-0.05T)= 0.95 T
![T\propto \dfrac{1}{\sqrt{g} }\\\\\dfrac{T}{T'}=\sqrt{\dfrac{g'}{g}}\\\\\dfrac{T}{0.95T}=\sqrt{\dfrac{g'}{9.8}}\\\\\dfrac{1}{0.95}=\sqrt{\dfrac{g'}{9.8}}\\\\1.1=\dfrac{g'}{9.8}\\\\g'=10.78\ m/s^2](https://tex.z-dn.net/?f=T%5Cpropto%20%5Cdfrac%7B1%7D%7B%5Csqrt%7Bg%7D%20%7D%5C%5C%5C%5C%5Cdfrac%7BT%7D%7BT%27%7D%3D%5Csqrt%7B%5Cdfrac%7Bg%27%7D%7Bg%7D%7D%5C%5C%5C%5C%5Cdfrac%7BT%7D%7B0.95T%7D%3D%5Csqrt%7B%5Cdfrac%7Bg%27%7D%7B9.8%7D%7D%5C%5C%5C%5C%5Cdfrac%7B1%7D%7B0.95%7D%3D%5Csqrt%7B%5Cdfrac%7Bg%27%7D%7B9.8%7D%7D%5C%5C%5C%5C1.1%3D%5Cdfrac%7Bg%27%7D%7B9.8%7D%5C%5C%5C%5Cg%27%3D10.78%5C%20m%2Fs%5E2)
So, the new value of acceleration due to gravity is
.