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Yuki888 [10]
3 years ago
7

During which changes of state do atoms overcome the attractive forces between them?

Physics
2 answers:
prohojiy [21]3 years ago
8 0
Atoms overcome the attractive forces between them through vaporization and sublimation .in vaporization the atoms are from gas to liquid while in sublimation it is from solid to gas which skips liquid state.through this the attractive force of the atoms does not meet in the liquid state because sublimation does not undergo in liquid phase. hope this help
Tems11 [23]3 years ago
6 0

Answer : The states in which atoms overcome the attractive forces between them are melting, evaporation and sublimation process.

Explanation :

Solid state : It is a state in which the particles are closely packed and does not have any space between them. The intermolecular force of attraction between the particles are more.

Liquid state : It is a state in which the particles are present in random and irregular pattern. The particles are closely arranged. The intermolecular force of attraction between the particles are lower than solid.

Gaseous state : It is a state in which the particles are loosely arranged and have a lot of space between them. The intermolecular force of attraction between the particles are very low.

The order of state in which atoms overcome the attractive forces between them are:

Solid state < Liquid state < Gaseous state

Thus, there are three states in which atoms overcome the attractive forces between them. The three states are:

Melting or fusion : It is a type of process in which the phase changes from solid state to liquid state at constant temperature.  That means, as we are move from solid state to liquid state the attractive forces are reduces.

Evaporation : It is a type of process in which the phase changes from liquid state to gaseous state at constant temperature.  That means, as we are move from liquid state to gaseous state the attractive forces are reduces.

Sublimation : It is a type of process in which the phase changes from solid state to gaseous state without passing through the liquid state at constant temperature.  That means, as we are move from solid state to gaseous state the attractive forces are reduces.

Hence, states in which atoms overcome the attractive forces between them are melting, evaporation and sublimation process.

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A force F acts in the forward direction on a cart of mass m. A friction force ff opposes this motion. Part A Use Newton's second
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Answer:

a = F-ff/m

Explanation:

According to Newton's second law of motion which states that "the rate of change in momentum of a body is directly proportional to the applied force F and acts in the direction of the force.

Mathematically;

F = ma

Since two forces acts on the cart i.e the moving force F and the frictional force Ff , we will take the sum of the forces.

∑F = ma where

m is the mass of the cart

a is its acceleration

∑F = F+(-ff )(since frictional force is an opposing force)

F - ff = ma

Dividing both sides by mass m

a = F-ff/m

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3 years ago
A proton that has a mass m and is moving at +164 m/s undergoes a head-on elastic collision with a stationary carbon nucleus of m
Irina18 [472]
The concept of this problem is the Law of Conservation of Momentum. Momentum is the product of mass and velocity. To obey the law, the momentum before and after collision should be equal:

m₁ v₁ + m₂v₂ = m₁v₁' + m₂v₂', where
m₁ and m₂ are the masses of the proton and the carbon nucleus, respectively,
v₁ and v₂ are the velocities of the proton and the carbon nucleus before collision, respectively,
v₁' and v₂' are the velocities of the proton and the carbon nucleus after collision, respectively,

m(164) + 12m(0) = mv₁' + 12mv₂'
164 = v₁' + 12v₂'  --> equation 1

The second equation is the coefficient of restitution, e, which is equal to 1 for perfect collision. The equation is

(v₂' - v₁')/(v₁ - v₂) = 1
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Solving equations 1 and 2 simultaneously, v₁' =  -138.77 m/s and v₂' = +25.23 m/s. This means that after the collision, the proton bounced to the left at 138.77 m/s, while the stationary carbon nucleus move to the right at 25.23 m/s.
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3 years ago
How can u tell matched forces act on objects?
mamaluj [8]

Answer:If an object's speed changes, or if it changes the direction it's moving in,

then there must be forces acting on it. There is no other way for any of

these things to happen.

Once in a while, there may be a group of forces (two or more) acting on

an object, and the group of forces may turn out to be "balanced".  When

that happens, the object's speed will remain constant, and ... if the speed

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3 0
3 years ago
An object is traveling on a circle with a radius of 6 feet. If in 80 seconds a central angle of 9/4 radians is swept out, then f
trapecia [35]

Answer:

The angular speed of the object is 0.0281 rad/s

The linear speed of the object is 0.169 ft/s

Explanation:

Given;

radius of the circle, r = 6 ft

time of motion of the object around the circle, t = 80 s

central angle formed by the object during the motion, θ = 9/4 rad = 2.25 rad

The angular speed of the object is calculated as;

\omega = \frac{\theta }{t} = \frac{2.25 \ rad}{80 \ s} = 0.0281 \ rad/s

The linear speed of the object is calculated as;

v = ωr

v = 0.0281 rad/s   x    6ft

v = 0.169 ft/s

8 0
3 years ago
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