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Sever21 [200]
2 years ago
13

Abc measures 90 and abd measures 25 what is the measurement of dbc

Mathematics
1 answer:
Mice21 [21]2 years ago
6 0

Answer:

Answer: The measurement of angle DBC is 65 degrees

Step-by-step explanation:

Line BD splits ABC into two angles ABD and DBC.

If ABC is 90 then the measures of ABD + DBC will be 90. Since we know the measure of ABD we can make this equation and solve it

\begin{gathered}90=25+x\\90-25=25+x-25\\65=x\end{gathered}

90=25+x

90−25=25+x−25

65=x

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40 POINTS!!!! ANSWER CORRECTLY PLZ
Grace [21]

Answer:

5. ○ \displaystyle \frac{25}{48}

4. ○ \displaystyle \frac{25}{46}

3. ○ \displaystyle \frac{31}{100}

2. ○ \displaystyle \frac{3}{4}

1. ○ \displaystyle \frac{27}{50}

Step-by-step explanation:

5. \displaystyle \frac{25}{23 + 25} = \frac{25}{48}

4. \displaystyle \frac{25}{46} = \frac{25}{21 + 25}

3. \displaystyle Flat-out\:given\:to\:you

2. \displaystyle \frac{21 + 23 + 31}{100} = \frac{75}{100} = \frac{3}{4}

1. \displaystyle \frac{31 + 23}{100} = \frac{54}{100} = \frac{27}{50}

I am joyous to assist you anytime.

7 0
3 years ago
Zia was driving his truck on the superhighway. His speed was recorded by the motorway camera between 6:00 am to 8:30 am. He cove
kodGreya [7K]

Answer:

Average speed = 100 km/h

Step-by-step explanation:

Given:

Total distance covered = 250 km

Total time taken = 8:30 am - 6:00 am = 2:30 hours = 2.5

Find:

Average speed.

Computation:

⇒ Average speed = Total distance covered / Total time taken

⇒ Average speed = 250 / 2.5

⇒ Average speed = 100 km/h

6 0
3 years ago
Which equation is true for x = 6? A) 2x + 5 = 25 B) 3x + 5 = 17 C) 5x − 18 = 7 D) 6x − 10 = 26
Anit [1.1K]
D is the answer.
6×6-10=26
4 0
3 years ago
Anyone know this I’m stuck?
alexandr1967 [171]

Answer:

The answer is B.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Is there any way to post images on your questions?
AysviL [449]

yeah there is u should be able to by clicking on the paper clip                                          


7 0
3 years ago
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