Let the number of bike be x and the number of skates be y, then
21x + 20y ≥ 362 . . . (1)
2y = x . . . (2)
Putting (2) into (1), then
21(2y) + 20y ≥ 362
42y + 20y ≥ 362
62y ≥ 362
y ≥ 5.84
The least number of pairs of skates they need to rent each day to make their minimum is 6.
First, we convert it into a unit like this
20 workers × 30 days = 600 units work
After leaving the 5 workers, we have 35 days to complete the work.
In 35 days only 15 workers will do the work.
So the work completed in 35 days by 15 workers = 35 ×15 =525 units
Remaining unit = 600 -525 =75 units
This unit would do by 5 workers in (75/5) = 15 days.
So after 15 days, 5 workers should leave the job.
Answer:
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