Question

A body moves s metres in a time t seconds so that s = t3 – 3t2 + 8. Find:

Answer 1

Answer is 3t²-6t

Step-by-step Explanation:-

$s(t) = {t}^{3} - 3 {t}^{2} + 8$

Now we need to find velocity. The velocity is the first derivative of position, so let's find the derivative of s(t) :-

$s'(t) = v(t) = 3 {t}^{3 - 1} - 3 \times 2 {t}^{2 - 1}$

So,

$v(t) = 3 {t}^{2} - 6t$

Therefore, v(t) = 3t²-6t