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Law Incorporation [45]
3 years ago
13

I need help putting these together in the correct place​

Mathematics
1 answer:
xeze [42]3 years ago
7 0

Answer:

whats do you mean by that whats the question ❓

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5x2 - 8 ÷ y - (7 + 14)<br><br> What is the value of the expression when x = 6 and y = 4?
rodikova [14]

Answer:

The answer is 157

Step-by-step explanation:

8/4= 8 divided by 4

5(6^2)-8/4-(7+14)

5(6^2)-8/4-(7+14)

=157

5 0
3 years ago
Read 2 more answers
What is represented by the letter "A"? What is represented by the letter<br> "B”<br><br> Plz help me
Maru [420]

Answer:

A: wavelength

B: amplitude

Step-by-step explanation:

8 0
3 years ago
calculate 4.5 times 10^negative 2 divided by 8.3 times 10^negative 4 by using scientific notation and the product rule. round an
Degger [83]

Answer:

5.4217 • 10¹

Step-by-step explanation:

4.5 • 10⁻² ÷ 8.3 • 10⁻⁴

450 ÷ 8.3

54.21686...

54.217

5.4217 • 10¹

I hope this helps

6 0
3 years ago
In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th
11111nata11111 [884]

Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

     Probability that the students passed the second exam = P(S) = 0.72

     Probability that the students passed both exams = P(F \bigcap S) = 0.58

Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = \frac{P(A\bigcap B)}{P(B) }

Similarly, P(S/F) = \frac{P(S\bigcap F)}{P(F) } = \frac{P(F\bigcap S)}{P(F) }  {As P(F \bigcap S) is same as P(S \bigcap F) }

                          = \frac{0.58}{0.74} = 0.784

Therefore, probability that he passed the second exam is 0.784 .

5 0
3 years ago
You forget the last two digits of your password for a website. What is the probability that you randomly choose the correct digi
Katen [24]
There are 100 possibilities for the last two digits  [ if we include 00].....therefore....you have  1/100 chance  [1 % ]  chance of choosing the correct one.....
7 0
3 years ago
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