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2 years ago

Exponential Growth & Decay - Guided Practice

Mathematics

2 answers:

dangina [55]2 years ago

4 0

$744.43, #3, and 17,922 ok

Nadusha1986 [10]2 years ago

4 0

in this image there are the asnwers from some of your questions

question 11. answer: 22554.45

Step-by-step explanation:

Since we are given a function to use to find the cost of the car, we first need to find the difference in the years 2017 and 2010

2017 - 2010 = 7

So our value for t will be 7.

We can use the formula because it still falls under the expected increase within the 10 year range.

So now let's substitute t in the function.

So it will cost the company $22554.45 to build the car in 2017.

10. answer:

$28,611.75

question 9.

Answer: 12,503 people

Step-by-step explanation:

This is an exponential decrease so to find the population in 8 years you have to use a future value formula:

= Amount * (1 + rate) ^ number of years

= 15,000 ( 1 + (-2.25%)) ⁸

= 15,000 * (1 - 2.25%)⁸

= 12,503.32

= 12,503 people

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56 POINTS! Find the area of the following figure. Explain how you got your answer.

AleksAgata [21]

Answer:

26.5 units²

Step-by-step explanation:

I am splitting the figure into a rectangle and two triangles to make this easier for me.

The rectangle is b•h so 5•4 = 20 units²

Area of triangle=1/2bh

The left triangle is $\frac{1}{2}$ (3•3) ---> $\frac{1}{2}$ (9) ---> 4.5 units²

The right triangle is $\frac{1}{2}$ (2•2) ---> $\frac{1}{2}$ (4) ---> 2 units²

Then add it all up: 20+4.5+2 = 26.5 units²

3 0

2 years ago

0.10(y-7)+0.08y=0.14y-0.4

SOVA2 [1]

Y=7.5

Isolate the variable by dividing each sides by factors that don't contain the variable. Hope this helps!

4 0

2 years ago

15 7/8 - 5 3/4

dem82 [27]

First, set ur denominator to lcm which is 8

15 7/8-5 6/8

= 10 1/8

8 0

2 years ago

What is the definition of an integer

ohaa [14]

A number that is not a fraction. It is a whole number.

7 0

3 years ago

Read 2 more answers

Evaluate the infinite sum:

satela [25.4K]

Consider the k-th partial sum,

$S_k = 1 + \dfrac2\pi + \dfrac3{\pi^2} + \cdots + \dfrac k{\pi^{k-1}}$

More compactly,

$\displaystyle S_k = \sum_{i=1}^k \frac i{\pi^{i-1}} = \frac{(1-\pi)k+\pi^{k+1}-\pi}{(1-\pi)^2\pi^{k-1}}$

(this is just another case of a similar sum you asked about a while ago [24494877])

The infinite sum is the limit of the partial sum as k goes to infinity. We have

$\displaystyle \lim_{k\to\infty} \frac{(1-\pi)k+\pi^{k+1}-\pi}{(1-\pi)^2\pi^{k-1}} = \frac\pi{(1-\pi)^2} \lim_{k\to\infty} \left(\frac{(1-\pi)k}{\pi^k} + \pi - \frac1{\pi^{k-1}} \right) = \boxed{\frac{\pi^2}{(1-\pi)^2}}$

since the non-constant terms in the limit converge to 0.

Alternatively, recall that for |x| < 1, we have

$\dfrac1{1-x} = \displaystyle \sum_{n=0}^\infty x^n$

Differentiating both sides gives

$\dfrac1{(1-x)^2} = \displaystyle \sum_{n=0}^\infty nx^{n-1} = \sum_{n=1}^\infty nx^{n-1}$

also valid for |x| < 1. Take x = 1/π and you get the sum you want to compute.

5 0

2 years ago