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xeze [42]
3 years ago
9

In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th

e students passed both exams. Assume a randomly selected student is selected from the class. If the student passed the first exam, what is the probability that they passed the second exam?
Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0

Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

     Probability that the students passed the second exam = P(S) = 0.72

     Probability that the students passed both exams = P(F \bigcap S) = 0.58

Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = \frac{P(A\bigcap B)}{P(B) }

Similarly, P(S/F) = \frac{P(S\bigcap F)}{P(F) } = \frac{P(F\bigcap S)}{P(F) }  {As P(F \bigcap S) is same as P(S \bigcap F) }

                          = \frac{0.58}{0.74} = 0.784

Therefore, probability that he passed the second exam is 0.784 .

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What is the equation table for y=x-15.
givi [52]

Answer:

Hope this Helps!!

Have a great day!!!

Step-by-step explanation:

x       y

-3    -18

-2     -17

-1      -16

0      -15

1       -14

2      -13

3      -12

4 0
2 years ago
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Is a vertical line a function
topjm [15]

Answer:

No

Step-by-step explanation:

Explanation 1)A vertical line can be represented by the equation x=a, where a can be any number. If you think about it, there is no y in the function, this making it not a function.

Explanation 2) For a line to be a function it has to pass the vertical line test, so you will draw a vertical line through the function and if it touches more than one point then it is not a function. In this case if you draw a vertical line through a vertical line there are an infinite number of places where the lines intercept, so it is not a function.

4 0
2 years ago
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The main cable of a suspension bridge forms a parabola, described by the equation y = a(x - h)2 + k, where y is the height in fe
nirvana33 [79]
Refer to the diagram shown below.

When x = 30 ft, the cable is at 15 ft, therefore y(30) = 15.
That is,
a(30 - h)² + k = 15            (1)

Also, because the distance between the supports is 90 ft, therefore
y(0) = 6 ft, and y(90) = 6 ft
That is,
a(-h)² + k = 6                 (2)
a(90 - h)² + k = 6          (3)

From (2) and (3), obtain
a(90 - h)² = ah²
90² - 180h + h² = h²
180h = 90²
h = 45 ft.

From (1) and (2), obtain
225a + k = 15
2025a + k = 6

Therefore
1800a = -9
a = - 0.005
k = 15 - 225(-0.005) = 16.125 ft

Answer:
The equation for the cable is
y = - 0.005(x - 45)² + 16.125 

A graph of the solution verifies that the solution is correct.

6 0
3 years ago
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Bill spent 70 on fertilizer and weed killer for his lawn .Each pound of fertilizer cost 50 cents and each once of weed killer co
meriva

An equation that correctly represent this relationship if x represents the number of pounds of fertilizer and y the number of ounces of weed killer is  0.5x + 3.5y = 70

<u>Solution:</u>

Given that, Bill spent 70 on fertilizer and weed killer for his lawn

Each pound of fertilizer cost 50 cents and each once of weed killer cost 3.50

We have to write an equation, if x represents the number of pounds of fertilizer and y the number of ounces of weed killer.

Now,<em> total amount = amount for fertilizers + amount for weed killers.</em>

Total amount = number of pounds of fertilizers x cost per pound + number of ounces of weed killer x cost per ounce.

\begin{array}{l}{\rightarrow 70=x \times 0.50+y \times 3.50} \\\\ {\rightarrow 0.5 x+3.5 y=70}\end{array}

Hence, the equation is 0.5x + 3.5y = 70

5 0
2 years ago
Find the distance between (4,6) and (-2, -2)
Nataly [62]

Answer:

\displaystyle d = 10

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (4, 6)

Point (-2, -2)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute [DF]:                     \displaystyle d = \sqrt{(-2-4)^2+(-2-6)^2}
  2. Subtract:                                \displaystyle d = \sqrt{(-6)^2+(-8)^2}
  3. Exponents:                            \displaystyle d = \sqrt{36+64}
  4. Add:                                       \displaystyle d = \sqrt{100}
  5. Evaluate:                               \displaystyle d = 10
8 0
2 years ago
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